If the two given six-sided number cubes contains the typical numbers starting from 1 to 6, the sum of the numbers will most likely be in the range of 6-9. Thus, for this item, the histogram that would best represent the scenario is the second column.
Answer:
53.2 kg
Step-by-step explanation:
Let E represent Esther's weight. Then Henry's weight is E/2, and David's weight is E-5.2. Their average weight is ...
((E-5.2) + E + (E/2))/3 = 42.6
2.5E -5.2 = 127.8 . . . . . . . . . . multiply by 3, simplify
2.5E = 133 . . . . . . . . . . . . . . . . add 5.2
E = 133/2.5 = 53.2 . . . . kg
Esther's weight is 53.2 kg.
Answer:
136
Step-by-step explanation:
72+64=136(discount=listed price -sp)
1. x^2 + y^2 - 4x + 12y - 20 = 0 ---- (x-2)^2 + (y+6)^2 = 60
3. 3x^2+ 3y^2 + 12x +18y - 15 = 0 --- (x+2)^2 + (y+3)^2 = 18
5. 2x^2 + 2y^2 - 24x - 16y - 8 = 0 --- (x-6)^2 + (y-4)^2 = 56
I don't know the other two, hope I helped though.
B) x=2 and y=14 i’m pretty sure lol
