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Alex_Xolod [135]
3 years ago
5

(05.02)

Mathematics
1 answer:
torisob [31]3 years ago
6 0

Answer:

4 jibovohvohbohvphhihbjh

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6a+5a= -11 sole each equation
iren [92.7K]

Answer:

789

Step-by-step explanation:

5 0
4 years ago
Round 1.5 to one decimal place
xxMikexx [17]
If the last digit in 1.50 is less than 5, then remove the last digit.

If the last digit in 1.50 is 5 or more and the second to the last digit in 1.50 is less than 9, then remove the last digit and add 1 to the second to the last digit.

If the last digit in 1.50 is 5 or more and the second to the last digit in 1.50 is 9, then remove the last digit, make the second to last digit 0, and add 1 to the number to the left of the decimal place.

When rounding 1.50 to one decimal place we use One Decimal Place Rule #1. Therefore, the answer to "What is 1.50 rounded to 1 decimal place?" is:

1.5
3 0
3 years ago
Read 2 more answers
Simplify the problem plss.
seropon [69]

Answer:

it is c

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
If r and s are positive integers, each greater than 1, and if 11(s-1) =13(r-1), what is the least possible value of (r+s)?
Tresset [83]

Answer:

The least value of (r+s) is (12+14)=26

Step-by-step explanation:

Well, first let us solve equation of 11(s-1)=13(r-1), which results in 11s-11=13r-13. Hence, 11s+2=13r. It is stated that r and s both are integers and greater than 1.

To make sure that r and s are integers, the least value of s must be equal to 14 (s=14) then the least value of r becomes 12 (r=12).

Finally, the least value of (r+s) is (12+14)=26.

4 0
4 years ago
Number of goals scored
Oksanka [162]

Answer:

a) 30 games

b) 66 points total

c) 2.2 points/ game

d) modal goals = 1

Step-by-step explanation:

a) 2 + 10 + 7 + 6 + 3 + 2 =  30 total games

b) (2*0) + (10*1) + (7*2) + (6*3) + (3*4) + (2*5)

0 + 10 + 14 + 18 + 12 + 10 = 66 total goals

c) 66 goals/ 30 games = 2.2 goals/ games

d) highest frequency of number of goals is 1 goal

8 0
3 years ago
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