Answer: The value of the house 2 years from now is $276,480.
Option (C) is correct.
According to the question,
Cost of house last year = $ 160000
Cost of house at present = $ 192000
The increase in the price of the house is calculated by finding the difference between the prices in two consecutive years.
Increment in cost = $ (192000-160000) =$ 32000
The rate of increment can be calculated by dividing the increment by the original price and then multiplying it by 100%.
Rate of increment = 32000/160000 * 100 =20%
Thus, the value of the house 2 years from now is calculated as:
=192000(1+20/100)(1+20/100)
=192000*120/100*120/100
= $ 276480
Step-by-step explanation:
Answer:
Try Khan Academy. They give lots of expression to find the greatest difference. It always helps me in this situation.
Step-by-step explanation:
Since this is a 30-60-90 triangle, the sides are in this proportion-
Shortest side (opposite of 30 degree angle)-x (v)
Longest side (opposite of 90 degree angle)-2x
Medium Side (opposite of 60 degree angle)- x(square root of 3)
So 23 is in the 2x proportion. x is v so solve for v like this-
23=2v
Divide 2.
v=11.5
Since v is x and x(square root of 3) is u, solve-
11.5*square root of 3
So-
v=11.5
u=11.5(square root of 3)
Yes, you are correct. I just put it in decimal form. :)
One of the easiest ways to do it is to divide 12.80 by 10 and then divide the result by 4:
12.80 / 10 = 1,28
1,28 / 4 = 0,32
I hope it will help you :)
