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Simplify the trigonometric expression.
Call the expression E:


So basically E is equivalent to

where the sign depends on which quadrant

lies. Shortly,

I hope this helps. =)
Tags: <em>simplify trigonometric trig expression sine cosine tangent sin cos tan absolute value modulus trigonometry</em>
1 is the answer because it is
X= 24 because both side lengths are the same size. So it would be 24. hope it helped.
16.935 I got a question on a test hope this helps):