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2 years ago

Find the area of the trapezoid below.

Mathematics

1 answer:

kvasek [131]2 years ago

3 0

18 cm doing the same thing rn

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ΔΑΒC Δ EDS What is the value of x?

Bas_tet [7]

Answer:

The value of x is 11 and CE = 40 and AC = 60

Step-by-step explanation:

Δ ΑΒC ≅ Δ EDS, therefore we have that:

24 / 36 = 3x + 7 / 6x - 6

Solving for x,

24 * (6x -6) = 36 * (3x + 7)

144x - 144 = 108x + 252

144x - 108x = 252 + 144

36x = 396

x = 396/36

x = 11 ⇒ 3x + 7 = 33 + 7 = 40; ⇒ 6x - 6 = 66 - 6 = 60

The value of x is 11 and CE = 40 and AC = 60

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2 years ago

Study the dashed arrows in the image.

nordsb [41]

Answer:

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2 years ago

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Perform the operation. Write the answer in standard form. (9 +3i) - (-2 - 7i)

ryzh [129]

Answer:

(9+3i)-(2-7i)=17i

Step-by-step explanation:

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2 years ago

Write the first five terms of the the sequence defined by the explicit formula an=72(1/3)^n-1

lisabon 2012 [21]

$a_n=72\left(\dfrac{1}{3}\right)^{n-1}\\\\\text{Put}\ n=1,\ n=2,\ n=3,\ n=4,\ n=5\ \text{to the equation}:\\\\n=1\to a_1=72\left(\dfrac{1}{3}\right)^{1-1}=72\left(\dfrac{1}{3}\right)^0=72(1)=72\\\\n=2\to a_2=72\left(\dfrac{1}{3}\right)^{2-1}=72\left(\dfrac{1}{3}\right)^1=72\left(\dfrac{1}{3}\right)=\dfrac{72}{3}=24\\\\n=3\to a_3=72\left(\dfrac{1}{3}\right)^{3-1}=72\left(\dfrac{1}{3}\right)^2=72\left(\dfrac{1}{9}\right)=\dfrac{72}{9}=8\\\\n=4\to a_4=72\left(\dfrac{1}{3}\right)^{4-1}=72\left(\dfrac{1}{3}\right)^3=72\left(\dfrac{1}{27}\right)=\dfrac{72}{27}=\dfrac{8}{3}\\\\n=5\to a_5=72\left(\dfrac{1}{3}\right)^{5-1}=72\left(\dfrac{1}{3}\right)^4=72\left(\dfrac{1}{81}\right)=\dfrac{72}{81}=\dfrac{8}{9}\\\\Answer:\ \boxed{72,\ 24,\ 8,\ \dfrac{8}{3},\ \dfrac{8}{9}}$

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3 years ago

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I’m so confused please help there’s a photo above btw

Strike441 [17]

Wow I don't get it either but my guess would be 9,6...sorry....

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3 years ago

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