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777dan777 [17]
3 years ago
6

Find the area of the trapezoid below.

Mathematics
1 answer:
kvasek [131]3 years ago
3 0
18 cm doing the same thing rn
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What is the value of x in the solution to this system of equations?
liberstina [14]

Answer:

x = 11

Step-by-step explanation:

Given the expression;

5x+2y=67 ...1

x=3y−7 ....2

Substitute 2 into 1

5(3y-7)+2y = 67

15y - 35 + 2y = 67

17y = 67+35

17y = 102

y = 102/17

y =6

Recall that x = 3y - 7

x = 3(6) - 7

x = 18 - 7

x = 11

Hence the value of x is 11

6 0
2 years ago
Which value below is included in the solution set for the inequality statement?
mixas84 [53]

You haven't provided any value, but I can tell you the solution set for the inequality.

First of all, expand both sides:

-3x+12 > 6x-6

Add 3x to both sides:

12 > 9x-6

Add 6 to both sides:

18 > 9x

Which is of course equivalent to

9x < 18

Divide both sides by 9

x < 2

So, every number smaller than 2 is part of the solution of this inequality.

7 0
2 years ago
Given the polynomial bellow which statement is true?
lions [1.4K]

Answer:

I think its A

Step-by-step explanation:

I factored the polynomial and its factors turned out to be (x-1)(x^2-2x-4), which eliminated the possibilities of 2 and 3. Then i replaced the (-1) in the place of the x and it turned out to be equal to 2, making the first statement true.

5 0
2 years ago
Help me with this asap plz
icang [17]

Answer:

30°

Step-by-step explanation:

RUT= RST ----since they both stand on common arc TR

Thus, RST = 30°

8 0
2 years ago
Read 2 more answers
A dog weighs two pounds less than three times the weight of a cat. The dog also weights twenty-two more pounds than the cat. Wri
8090 [49]

Answer:

Weight of dog: 34 pounds,

Weight of cat: 12 pounds.

Step-by-step explanation:

Let d represent weight of dog and c represent weight of cat.

We have been given that a dog weighs two pounds less than three times the weight of a cat.

3 times weight of cat: 3c

We can represent the given information in an equation as:

d=3c-2...(1)

We are also told that the dog also weights twenty-two more pounds than the cat. We can represent the given information in an equation as:

d=c+22...(2)

Equate both equations:

3c-2=c+22

3c-c-2=c-c+22

2c-2=22

2c-2+2=22+2

2c=24

\frac{2c}{2}=\frac{24}{2}

c=12

Therefore, the weight of cat is 12 pounds.

Substitute c=12 in equation (2)

d=c+22

d=12+22

d=34

Therefore, the weight of dog is 34 pounds.

4 0
3 years ago
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