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3 years ago

9

Tamanika got a raise in her hourly pay, from $15.50 to $17.85. Find the percent increase. Round to the nearest tenth of a percen

t.

1 answer:

ra1l [238]3 years ago

4 0

Answer:

13.2%

or 115.2%

Step-by-step explanation:

hope it's correct. lemme know which one is correct

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On a certain hot summer's day, 538 people used the public swimming pool. The daily prices are $1.75 for children and $2.25 for a

Artist 52 [7]

Answer:

The number of children was 170 and adults was 368.

Step-by-step explanation:

To clarify we'll call children by 'c' and adults by 'a'. The amount of people in the pool should be the sum of adults and children, so:

a + c = 538

The receipts for the adimission should total the amount of tickets from children and adults multiplied by the price of each ticket, so:

1.75*c + 2.25*a = 1125.5

We now have two equations and two variables. Using the first equation we can isolate the 'a' variable and use it on the second equation to find an answer. We then have:

a + c = 538

a = 538 - c

Using it on the second equation:

1.75*c + 2.25*(538-c) = 1125.5

1.75*c + 1210.5 - 2.25*c = 1125.5

1.75*c - 2.25*c = 1125.5 - 1210.5

-0.5*c = -85

c = -85/(-0.5) = 170

Using this value on the first equation:

a = 538 - 170 = 368

7 0

3 years ago

Read 2 more answers

Help please I don’t understand

ollegr [7]

Answer:

y = -1/10

Step-by-step explanation:

-2/5 + y = -1/2 First, make a common denominator for the fractions

-4/10 + y = -5/10

+4/10 +4/10 Add 4/10 to both sides

y = -1/10

8 0

4 years ago

Mariela earned the following test scores in math: 95, 90, 100, 85, 80 Mr. Adams accidentally entered Mariela’s next test score a

Vesnalui [34]

Answer:

Before the error, the mean and the median were both 90.

The error added an outlier to the data set.

After the error, the mean was 75 and the median was 87.5

The mean was impacted by the error more than the median

Step-by-step explanation:

First is to put the data in order from smallest to largest

80,85,90,95,100

The mean is add up the data and divide by the number of points. The median is the middle of the data

Mean = (80+85+90+95+100)/5=450/5 = 90

Median = 90

When a 0 is added

0, 80,85,90,95,100

There is now an outlier, which is a data point far away from the others

Mean = (0+80+85+90+95+100)/6=450/6 = 75

Median = (85+90)/2 = 87.5

When the data set is even, take the two middle numbers and average them

The mean was impacted more than the median. It went from 90 to 75, where the median went from 90 to 87.5

5 0

3 years ago

Read 2 more answers

Stephanie took a science exam that had two parts. Part 1: She got 16 questions correct, which was 45 of the number of part 1 que

vesna_86 [32]

Given :

Stephanie took a science exam that had two parts. Part 1: She got 16 questions correct, which was 4/5 of the number of part 1 questions. Part 2: She got 16 questions correct, which was 2/3 of the number of part 2 questions.

To Find :

The total number of questions on Stephanie's exam.

Solution :

Let, number of questions in Part 1 is x :

$16=\dfrac{4}{5}x\\\\x=20$

Let, number of questions in Part 2 is y :

$16=\dfrac{2}{3}y\\\\y=24$

Therefore, total number of questions on Stephanie's exam are 20 + 40 = 60.

Hence, this is the required solution.

5 0

3 years ago

Rectangle ABCD is graphed in the coordinate plane. The following are the vertices of the rectangle:

In-s [12.5K]

$\huge\boxed{11\ \text{units}}$

To solve this, we need to find the distance between points C and D.

The distance formula is:

$\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the values from points $C(x_1, y_1)$ and $D(x_2, y_2)$ .

$\sqrt{(-4-(-4))^2+(-5-6)^2}$

Subtract.

$\sqrt{0^2+(-11)^2}$

Evaluate the powers.

$\sqrt{0+121}$

Solve for the final answer.

$\sqrt{121}\\\boxed{11}$

8 0

2 years ago