Answer:
The probability that any 7 randomly chosen parking spots have 2 SUVs and 5 trucks or 3 SUVs and 4 trucks is 49/60
The probability that of any 7 randomly chosen vehicles, exactly 1 is an SUV is = 7/40
Step-by-step explanation:
probability of taking 7 vehicles from 10 vehicles = 10C₇
number of ways taking 2 SUVs and 5 trucks = 3C₂* 7C₅ = 63
number of ways taking 3 SUVs and 4 trucks =3C₁*7C₄ = 35
number of ways taking 2 SUVs and 5 trucks or 3 SUVs and 4 trucks = 63 + 35 = 98
The probability that any 7 randomly chosen parking spots have 2 SUVs and 5 trucks or 3 SUVs and 4 trucks is = 98/120 = 49/60
number of ways taking 7 randomly chosen vehicles, exactly 1 is an SUV = 3C₁*7C₆ = 21
The probability that of any 7 randomly chosen vehicles, exactly 1 is an SUV is 21/120 = 7/40
Answer:
<em>Two adjacent angles are supplementary.</em>
Answer:
(4,2)
Step-by-step explanation:
(4)-4(2)=-4
5(4)-4(2)=12
a)x^2+2x
we can factorise this by x
x(x+2)
b)2x^2-6x
we can factorise this by 2x
2x(x-3)
c)15x-10x^3
we can factorise this by 5x
5x(3-2x^2)
d)9x^2+3x^3
this can be factorised by 3x^2
3x^2(3+x)
Answer:
the equations are coincident.
Step-by-step explanation: