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sasho [114]
4 years ago
15

olivia has 2 gallons and 3 quarts of vanilla ice cream and 1 gallon and 2 quarts of ice cream left over form the party how many

gallons and quarts does she have left
Mathematics
1 answer:
stealth61 [152]4 years ago
3 0

Answer:

She has 4 gallons and 1 quart left

Step-by-step explanation:

4 quarts equals a gallon. Add the 2 gallons with the one gallon and it's 3 gallons. Then add the 3 quarts with the other 2 quarts for another gallon with a quart left over. Add that gallon with the other three and she has 4 gallons and 1 quart. Hope this helps :>

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Which ratios are equal to 64 when the scale factor is 8? Select all that apply.
Luden [163]

Answer:

The scaled surface area of a square pyramid to the original surface area.

The scaled area of a triangle to the original area.

Step-by-step explanation:

Suppose that we have a cube with sidelength M.

if we rescale this measure with a scale factor 8, we get 8*M

Now, if previously the area of one side was of order M^2, with the rescaled measure the area will be something like (8*M)^2 = 64*M^2

This means that the ratio of the surfaces/areas will be 64.

(and will be the same for a pyramid, a rectangle, etc)

Then the correct options will be the ones related to surfaces, that are:

The scaled surface area of a square pyramid to the original surface area.

The scaled area of a triangle to the original area.

5 0
3 years ago
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postnew [5]
The answer is complex number

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the imaginary part is the 'bi' part of the a+bi

answer is A
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answer is A
5 0
4 years ago
Find the exact value of tan (arcsin (two fifths)). For full credit, explain your reasoning.
Hitman42 [59]
\bf sin^{-1}(some\ value)=\theta \impliedby \textit{this simply means}
\\\\\\
sin(\theta )=some\ value\qquad \textit{now, also bear in mind that}
\\\\\\
sin(\theta)=\cfrac{opposite}{hypotenuse}\qquad 
\qquad 
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}\\\\
-------------------------------\\\\

\bf sin^{-1}\left( \frac{2}{5} \right)=\theta \impliedby \textit{this simply means that}
\\\\\\
sin(\theta )=\cfrac{2}{5}\cfrac{\leftarrow opposite}{\leftarrow hypotenuse}\qquad \textit{now let's find the adjacent side}
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\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}

\bf \pm \sqrt{5^2-2^2}=a\implies \pm\sqrt{21}=a
\\\\\\
\textit{we don't know if it's +/-, so we'll assume is the + one}\quad \sqrt{21}=a\\\\
-------------------------------\\\\
tan(\theta)=\cfrac{opposite}{adjacent}\qquad \qquad tan(\theta)=\cfrac{2}{\sqrt{21}}
\\\\\\
\textit{and now, let's rationalize the denominator}
\\\\\\
\cfrac{2}{\sqrt{21}}\cdot \cfrac{\sqrt{21}}{\sqrt{21}}\implies \cfrac{2\sqrt{21}}{(\sqrt{21})^2}\implies \cfrac{2\sqrt{21}}{21}

7 0
3 years ago
How do we know a given number in the radical is whether rational or irrational​
raketka [301]

number is described as rational if it can be written as a fraction (one integer divided by another integer). A number is irrational if it cannot be written as a fraction. The decimal form of an irrational number does not terminate or recur.

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Answer:

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Step-by-step explanation:

5 0
3 years ago
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