For this case we have that by definition, the momentum equation is given by:
Where:
m: It is the mass
v: It is the velocity
According to the data we have:
Substituting:
On the other hand, if we clear the variable "mass" we have:
According to the data we have:
Thus, the mass is 
Answer:
On the dog's return trip (between <em>t</em> = 10 and <em>t</em> = 12.5 seconds), the slope of the position function is steeper than during the first 5 seconds, which means the dog ran home faster. The only option that captures this is D.
You can check to make sure that the dog indeed runs twice as fast on the return trip. The slope of the position function during the first 5 seconds is
(change in position) / (change in time) = (5 - 0) / (5 - 0) = 5/5 = 1
while during the return trip, it is
(0 - 5) / (12.5 - 10) = -5/2.5 = -2
Ignoring the sign (which only indicates the direction in which the dog was running), we see that the dog's speed on the return trip was indeed twice as high as during the first 5 s.
Answer:
a = 40 [m/s²]
Explanation:
These kinds of problems can be solved using Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.
∑F = m*a
where:
F = force = 6 [N]
m = mass = 0.15 [kg]
a = acceleration [m/s²]
![a=F/m\\a=6/0.15\\a=40[m/s^{2} ]](https://tex.z-dn.net/?f=a%3DF%2Fm%5C%5Ca%3D6%2F0.15%5C%5Ca%3D40%5Bm%2Fs%5E%7B2%7D%20%5D)
Answer:
So 240V RMS is equivalent to 339 V peak, or 679 V peak to peak and can be written as 240 Vrms. (the formula is Vrms = Vmax / √2). The waveform is a sinusoid varying about a neutral, which can also be drawn as a vector with a single arrow pointing away from neutral.
