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Sidana [21]
3 years ago
11

A turntable must spin at 33.4 rpm (3.50 rad/s) to play an old-fashioned vinyl record. how much torque must the motor deliver if

the turntable is to reach its final angular speed in 1.0 revolutions, starting from rest? the turntable is a uniform disk of diameter 30.5 cm and mass 0.21 kg.
Physics
1 answer:
Westkost [7]3 years ago
4 0
In order to compute the torque required, we may apply Newton's second law for circular motion:
Torque = moment of inertia * angular acceleration

For this, we require the angular acceleration, α. We may calculate this using:
α = Δω/Δt
The time taken to achieve rotational speed may be calculated using:
time = 1 revolution * 2π radians per revolution / 3.5 radians per second
time = 1.80 seconds

α = (3.5 - 0) / 1.8
α = 1.94 rad/s²

The moment of inertia of a thin disc is given by:
I = MR²/2
I = (0.21*0.1525²)/2
I = 0.002

τ = 1.94 * 0.002
τ = 0.004

The torque is 0.004
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Each of the following diagrams shows a spaceship somewhere along the way between Earth and the Moon (not to scale); the midpoint
djyliett [7]

Answer:

F_5 >F_4>F_1 >F_2>F_3

Where F_i represent the force for each of the 5 cases i -1,2,3,4,5 presented on the figure attached.

Explanation:

For this case the figure attached shows the illustration for the problem

We have an inverse square law with distance for the force, so then the force of gravity between Earth and the spaceship is lower when the spaceship is far away from Earth.

Th formula is given by:

F = G \frac{m_{Earth} m_{Spaceship}}{r^2}

Where G is a constant G = 6.674 x10^{-11} m^2/ (ks s^2)

m_{Earth} represent the mass for the earth

m_{spaceship} represent the mass for the spaceship

r represent the radius between the earth and the spaceship

For this reason when the distance between the Earth and the Spaceship increases the Force of gravity needs to decrease since are inversely proportional the force and the radius, and for the other case when the Earth and the spaceship are near then the radius decrease and the Force increase.

Based on this case we can create the following rank:

F_5 >F_4>F_1 >F_2>F_3

Where F_i represent the force for each of the 5 cases i -1,2,3,4,5 presented on the figure attached.

6 0
3 years ago
A hiker climbs a mountain. Starting at the base of the mountain, he first moved up 520m at a 32.0 degree angle. What is the fina
balu736 [363]

Answer:

\displaystyle \vec{d}=

Explanation:

<u>Displacement Vector</u>

Suppose an object is located at a position  

\displaystyle P_1(x_1,y_1)

and then moves at another position at

\displaystyle P_2(x_2,y_2)

The displacement vector is directed from the first to the second position and can be found as

\displaystyle \vec{d}=

If the position is given as magnitude-angle data ( z , α), we can compute its rectangular components as

\displaystyle x=z\ cos\alpha

\displaystyle y=z\ sin\alpha

The question describes the situation where the initial point is the base of the mountain, where both components are zero

\displaystyle P_1(0,0)

The final point is given as a 520 m distance and a 32-degree angle, so  

\displaystyle x_2=520\ cos32^o= 440.99\ m

\displaystyle y_2=520\ sin32^o=275.6\ m

The displacement is

\displaystyle \vec{d}=

5 0
3 years ago
An elevator filled with passengers has a mass of 1683 kg. (a) The elevator accelerates upward from rest at a rate of 1.20 m/s2 f
artcher [175]

Answer:

the tension is 18513N

Explanation:

Given that

mass = 1683kg

acceleration = 1.2m/s^2

acceleration due to gravity = 9.8m/s^2

T-mg =   ma

T = ma + mg

T = m(a +g)

T = 1683 kg(1.20 m/s2 + 9.8)

T = 1683 (11)

T = 18513N

therefore, the tension is 18513N

4 0
3 years ago
Read 2 more answers
Question is down below need rply fast
My name is Ann [436]

The X and Y components are as follows;

1. X = 35 * cos 57 = 19. 1m/s; Y = 35 * sin 57 = 29.4 m/s

2. X = 12 * -cos 34  = -10 m/s; Y = 12 * -sin 34 = -6.7 m/s

3. X = 8 * -cos 90  = 0 m/s; Y = 12 -sin 90 = -8 m/s

4. X = 20 * cos 75 = 5. 2m/s; Y = 20 * (-sin 75) =  -19.3 m/s

<h3>What are the horizontal and vertical components of the vectors?</h3>

The horizontal and vertical components of the velocities are given as follows:

  • Horizontal component, X = x cos θ
  • Vertical component, Y = y sin θ

1. 35 m/s at  57° from x-axis

X = 35 * cos 57 = 19. 1m/s

Y = 35 * sin 57 = 29.4 m/s

2. 12m/s at 34° S of W

X = 12 * -cos 34  = -10 m/s

Y = 12 * -sin 34 = -6.7 m/s

3. 8 m/s at South

X = 8 * -cos 90  = 0 m/s

Y = 12 -sin 90 = -8 m/s

4. 20 m/s at  275° from x-axis

X = 20 * cos 75 = 5. 2m/s

Y = 20 * (-sin 75) =  -19.3 m/s

In conclusion, the X and Y components are found by taking cosines and sine of the angles.

Learn more about horizontal and vertical components at: brainly.com/question/26446720

#SPJ1

8 0
2 years ago
A boy holds a heavy package for one hour. He is very tired but has not done any work. Explain why he did not do any work.
Feliz [49]

Answer:he's not applying force or motion

Explanation:

p=f & m

5 0
2 years ago
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