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Phantasy [73]
3 years ago
7

Please help me find out this answer

Physics
1 answer:
Elanso [62]3 years ago
4 0
The direction of work.........

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A completely inelastic collision occurs between two balls of wet putty that move directly toward each other along a vertical axi
Marrrta [24]

Answer:

h = 2.64 meters      

Explanation:

It is given that,

Mass of one ball, m_1=3\ kg

Speed of the first ball, v_1=20\ m/s (upward)

Mass of the other ball, m_2=2\ kg

Speed of the other ball, v_2=-12\ m/s (downward)

We know that in an inelastic collision, after the collision, both objects move with one common speed. Let it is given by V. Using the conservation of momentum to find it as :

V=\dfrac{m_1v_1+m_2v_2}{m_1+m_2}

V=\dfrac{3\times 20+2\times (-12)}{3+2}

V = 7.2 m/s

Let h is the height reached by the combined balls of putty rise above the collision point. Using the conservation of energy as :

mgh=\dfrac{1}{2}mV^2

h=\dfrac{V^2}{2g}

h=\dfrac{7.2^2}{2\times 9.8}

h = 2.64 meters

So, the height reached by the combined mass is 2.64 meters. Hence, this is the required solution.

5 0
3 years ago
Approximately what percent of the Visible illuminated moons surface is seen in this phase
Firlakuza [10]

well i see 25 % but half of the visable surface is illuminated

8 0
3 years ago
What are the very small particles that make up matter​
mrs_skeptik [129]
Atoms
Hope this helps!!
4 0
3 years ago
Read 2 more answers
A sail boat moves north for a distance of 10 km when blown by a wind 30° east of south with the force of 5.00×10^4 N. how much w
erma4kov [3.2K]
<h3><u>Answer;</u></h3>

a) 5.00 x 10^8 J

<h3><u>Explanation;</u></h3>

The work done to move the sailboat is calculated through the equation;

W = F x d

where F is force and d is the distance.

Substituting the known values from the given above,

                             W = (5.00 x 10⁴ N)(10 km)(1000 m/ 1km)

                                 = 5.00 x 10⁸ J

Thus, the work done is <u>5.00 x 10⁸Joules</u>

7 0
3 years ago
The half-life of radium-226 is 1600 years. How many
Alenkinab [10]

Answer:

1600 years half life

3200/1600 is 2 half lifes

first half life takes the sample to 1/2 it's original amount and the second takes it to 1/4 of it's original amount

so 1/4*7gm is 1.75gm

Explanation:

7 0
3 years ago
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