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Phantasy [73]
3 years ago
7

Please help me find out this answer

Physics
1 answer:
Elanso [62]3 years ago
4 0
The direction of work.........

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The newton is defined as the:
irakobra [83]

The Newton is defined as the:

C. Force that can give a 1-kilogram mass an acceleration of 1m/sec squared.

<h3>Hope it helps..</h3>

ray4918 here

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2 years ago
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Select the correct answer.
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For the scale od the paraboliczne curviczne Ur
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A hockey puck of mass m1=165 g slides from left to right with an initial velocity of 15.5 m/s. It collides head on with a second
Fynjy0 [20]

Answer:

it may be -6 m/s

Explanation:

3 0
3 years ago
Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! 39 points and will give branlist asap!
xz_007 [3.2K]

Answer:

Graph for object that is not moving: B

Graph for object that is speeding up: D

Explanation:

A.) In order to represent that an object is not moving, you must either show that there is no velocity (0 m/s) or show a position over time graph that is a horizontal line.

Because the position is the same as time increases, the graph shows that there the object must be at rest, as there is no change in position due to velocity. (Velocity must be 0m/s)

B.) In order to represent an object is speeding up, the position time graph must either be a positive exponential function, the velocity time graph must be a positive, linear line, or the acceleration over time graph must be a positive, horizontal line.

Why is D the correct answer? Because if an object is speeding up, you know that the value of its speed (velocity) is increasing at some rate. And since speeding up refers to positive change, the function of velocity over time graph must be a positive function.

7 0
3 years ago
What net force is needed to increase the velocity of a 5 kg object by 3 m/s over the course of 2.5 seconds?
mixer [17]

Hi there!

Recall Newton's Second Law:

\large\boxed{\Sigma F = ma}

∑F = net force (N)

m = mass (kg)

a = acceleration (m/s²)

We must begin by solving for the acceleration using the following:

a = Δv/t

In this instance:

Δv = 3 m/s

t = 2.5 sec

a = 3/2.5 = 1.2 m/s²

Now, plug this value along with the mass into the equation for net force:

\Sigma F = 5(1.2) = \boxed{6 N}}

6 0
3 years ago
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