The answer is no more water.
3/4=9/12
3/4
From 3 to 9 it is X3 and from 4 to 12 it is X3.So you take 3*3 which is nine and 4*3 which is 12 and now you have this
9/12=9/12
The nearest tenth of how fast a rover will hit Mars' surface after a bounce of 15 ft in height is 20.7ft/s.
<h3>What is the approximation about?</h3>
From the question:
Mars: F(x) = 2/3
Therefore, If x = 15
Then:
f (15) = 2/3 ![\sqrt[8]{15}](https://tex.z-dn.net/?f=%5Csqrt%5B8%5D%7B15%7D)
= 16/3
= 20.7ft/s
Hence, The nearest tenth of how fast a rover will hit Mars' surface after a bounce of 15 ft in height is 20.7ft/s.
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<span> Start with the given equation
Subtract 6 from both sides.
Combine like terms.
Now let's graph </span>