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otez555 [7]
3 years ago
14

How many hours in five days​

Mathematics
2 answers:
Ray Of Light [21]3 years ago
6 0

Answer:

There are 120 hours in 5 days.

pogonyaev3 years ago
4 0

Answer:

5 days = 120 hours

Step-by-step explanation:

One day = 24 hours

5 days = 24*5 hours = 120 hours

It mostly just plain unitery method

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Determine all real numbers a$ such that the inequality $ |x^2 2ax 3a|\le2$ has exactly one solution in x$.
vovikov84 [41]

Answer:

x=-1, S=\{x\:\in\mathbb{R}:x=-1\}

Step-by-step explanation:

For the sake of clarity, assuming you meant:

|x^{2}+2x+3|\le2

1) Absolute Value or Modulus functions has one property that assures us that:

If |a|

2) Solving for x

I) x^{2}+2x+3\geqslant -2\Rightarrow x^{2}+2x+5\geqslant 0 \Rightarrow x\geqslant \frac{-2\pm \sqrt{2^{2}-4*1*5}}{2} x'\geqslant \frac{-2+4i }{2} \:and\:x''\geqslant \frac{-2-4i }{2}

Not defined in Real Set of Numbers

Evaluating x^{2}+2x+3\leqslant 2:

x^{2}+2x+3\leqslant 2\\x^{2}+2x+1\leqslant 0\\(x+1)(x+1)\leqslant 0 \Rightarrow S=\{-1\}

3) So, since for the first case the Discriminant Δ <0, then the solutions presented for x^{2}+2x+3\geqslant -2\: \in \mathbb{C}. The only solution in the Real Set for the inequality |x^{2}+2x+3|\le2 is S=\{-1\}, i.e. x=-1.

8 0
3 years ago
Write a doubles fact that can help me solve 6+5=11
aev [14]
Well if 5+5=10 adding 1 would give you 11. Or you could do 6+6=12 and then subtract 1. Both 5+5 and 6+6 are doubles facts.
5 0
4 years ago
PLS HELP AN OGRE OUT Marco has drawn a line to represent the perpendicular cross-section of the triangular prism. Is he correct?
Rzqust [24]

Answer:

The correct option is;

Yes, the line should be perpendicular to one of the rectangular faces

Step-by-step explanation:

A perpendicular cross-section of a triangular prism resting on a rectangular face will have a triangular cross-section section an either side of the line of the cross-section, therefore we have;

Given that the triangular prism is lying on one of the rectangular faces, the perpendicular cross-section will be represented by a line drawn along the slant height of the triangular prism, therefore the correct option is yes, the line should be perpendicular to one of the rectangular faces.

5 0
4 years ago
Help please will mark best answer
77julia77 [94]
I figured out the first question, the second one in lost on.

\frac{(6-x)}{x^2+3x-28} / \frac{x^2-36}{x^2+5x-36}

Factor both of the equations, numerator and denominator

\frac{(6-x)}{(x+7)(x-4)}*  \frac{(x+6)(x-6)}{(x+9)(x-4)}

Cancel the like factors *excuse the zero im just showing you*

\frac{(0)}{(x+7)} *\frac{(x+6)}{(x-9)}

Combine frunctions

\frac{(6+x)}{(x-9)(x+7)}

x-9=0
x+7=0

Restrictions are 9 and -7
4 0
4 years ago
Find an equation for each line using Y=mX+b Plzzz help!
DaniilM [7]

Answer:

i believe that all of them are right, if they are not please correct me

Step-by-step explanation:

<em>m= y= 2x +4 </em>

<em>p=  y= 1x- 1</em>

<em>n=  y= -4x </em>

<em>L=  y= 0x+ 4</em>

hope this helps!

5 0
3 years ago
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