Subtract the fractions 6/8

$\frac{height \hspace{0.1cm} of \hspace{0.1cm} ammunition \hspace{0.1cm} box}{height \hspace{0.1cm} of \hspace{0.1cm} each \hspace{0.1cm} crate} = \frac{10 \hspace{0.1cm} feet}{12 \hspace{0.1cm} inches} = \frac{10 \times 12 \hspace{0.1cm} inches }{12 \hspace{0.1cm} inches} = 10 \hspace{0.1cm} crates$

where 1 foot = 12 inches. SO the answer is that a maximum of 10 crates can be stacked from floor to ceiling.

Step-by-step explanation:

i) the maximum number of crates that can be stacked between the floor and ceiling

$\frac{height \hspace{0.1cm} of \hspace{0.1cm} ammunition \hspace{0.1cm} box}{height \hspace{0.1cm} of \hspace{0.1cm} each \hspace{0.1cm} crate} = \frac{10 \hspace{0.1cm} feet}{12 \hspace{0.1cm} inches} = \frac{10 \times 12 \hspace{0.1cm} inches }{12 \hspace{0.1cm} inches} = 10 \hspace{0.1cm} crates$

where 1 foot = 12 inches

3 0

3 years ago

Dave has a 32-ounce energy drink. He drinks 10 ounces. Enter the percentage of ounces Dave had left from his energy drink. Round

balandron [24]

68.75 percent hope this helps

3 0

4 years ago

Read 2 more answers

The greatest number of bat bags the coach can buy with $605 is

Studentka2010 [4]

Answer:

11

12

does not

Step-by-step explanation:

If we know how much money the coach has and how much each bag costs we can find out how much bags the coach can by by divide the money the coach has by the price of one bat bag. So we do....

605 / 55 = 11

So now we know that she can by 11 bags maximum, while she needs 12 bags for the team. From this we know that she does not have enough money to buy 12 bags.

7 0

3 years ago

Subtract the fractions 6/8 - 4/6 =