we have been given that in ΔFGH, the measure of ∠H=90°, GF = 53, HG = 28, and FH = 45. We are asked to find the ratio that represents the sine of ∠G.
First of all, we will draw a right triangle using our given information.
We know that sine relates opposite side of right triangle with hypotenuse.
We can see from the attachment that opposite side to angle G is FH and hypotenuse is GF.
Therefore, the ratio 
represents the sine of ∠G.
The vertex of the given parabola is the point (3, 25).
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How to get the vertex of the parabola?</h3>
If the parabola has roots x₁ and x₂, then the vertex of the parabola is at:
xₙ = (x₁ + x₂)/2
Here the parabola is:
y = (-2 - x)*(x - 8)
We can rewrite that to:
y = -(x + 2)*(x - 8)
Then the two roots are:
x = -2 and x = 8
Then the vertex is at:
xₙ = (8 - 2)/2 = 6/2 = 3
To get the y-value of the vertex, we evaluate the equation in x = 3:
y = -(3+ 2)*(3 - 8) = -5*(-5) = 25
The vertex is (3, 25).
If you want to learn more about parabolas:
brainly.com/question/4061870
#SPJ1
The limand is continuous at
, so you can directly substitute
to get
Did you mean to write
in the denominator by any chance? In that case, you would instead have
X=15
90 + 5(15) + 15 = 180
90 + 75 + 15 = 180
180 = 180
To get 15, I added up the the x's (which was 6 total), and divided 90 by them.
90/6 = 15
Then you just fill them into the equation.
Have a superb day!
