Answer:
4x - 5 > 7 = [3,∞)
Step-by-step explanation:
Move all terms not containing x to the right side of the inequality.
4x<u> > </u>12
Divide each term by 4 and simplify.
x <u>> </u>3
Convert the inequality to interval notation.
[3,∞)
I hope this helps
if you could, feel free to mark me Brainliest it would be much appreciated :D
Answer:
6 bc yes
Step-by-step explanation:
Answer:
D) The graph and the table
Step-by-step explanation:
The equation and the verbal description fully represent the situation because their representation is valid for all possible x values. On the other hand, the table and the graph only represent certain x values.
Firstly, found out a square that is 7cm long and 5cm wide, you get the 7 from adding 5+2 across the top. Don't forget that, 2cm = 5m so you get the real area we need to work out how many meters are in each length.
So, firstly you know that in 1 cm there is 2.5m, with this information you can then do 7x2.5 to get the distance across the top in meters. That gives you 17.5 megers for the top and 5x2.5 = 12.5m.
After finding that, you have to find the area of this square, so you do 17.5m x 12.5m = 218.75m^2 for the biggest square, that's the total area however we want the bedroom area.
Therefore we have to workout how much area is in the living room and take that away from the total amount. Since we found out how many meters are in the 5cm we can use that here again. 12.5m x 12.5m = 156.25m^2 with this we do 218.75m^2 - 156.25m^2 = 62.5m^2 is for the bedroom and small empty space. now we just need to find the small empty space.
To do that, we do 5-4 which leave us with 1 cm and we already know it's across length is 2, with the information provided and stated we know that it's 2.5m x 5m = 12.5m^2
Then finally we do 62.5m^2 - 12.5m^2 to get the bedroom area. <u>50m^2</u>
This is a great question!
To determine the probability with which two sweets are not the same, you would have to subtract the probability with which two sweets are the same from 1. That would only be possible if she chose 2 liquorice sweets, 5 mint sweets and 3 humburgs -
As you can see, the first time you were to choose a Liquorice, there would be 12 out of the 20 sweets present. After taking that out however, there would be respectively 11 Liquorice out of 19 remaining. Apply the same concept to each of the other sweets -
____
Calculate the probability of drawing 2 of each, add them together and subtract from one to determine the probability that two sweets will not be the same type of sweet!
<u><em>Thus, the probability should be 111 / 190</em></u>
