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Lemur [1.5K]
3 years ago
13

Bonus problem. Find the ratio a :b if it is given that 3a=8b​

Mathematics
1 answer:
steposvetlana [31]3 years ago
3 0

Answer:

a:b = 8:3

Step-by-step explanation:

To find the ration, we want to get in equation in the form \frac{a}{b} =\frac{x}{y}.

We can start by dividing by b on both sides:

3a = 8b

÷b     ÷b

\frac{3a}{b} = 8

Now, we can divide by 3 on both sides to get:

\frac{a}{b} = \frac{8}{3}

We can change the format into a ratio:

a:b = 8:3

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Answer:

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Drop an altitude. Either of the two resulting right triangles with legs of length 5 and x and a hypotenuse of 10.

By the Pythagorean theorem, it follows that the answer is B.

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What interger is equivalent
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1. Given f(x) =1/4 (x – 8), what is the value of f(24)?
goldenfox [79]

Hi there!  

»»————- ★ ————-««

I believe your answer is:  

f(24)=4

»»————- ★ ————-««  

Here’s why:  

⸻⸻⸻⸻

f(x)=\frac{1}{4}(x-8)\\-----------\\\rightarrow f(24)= \frac{1}{4}(24-8)\\\\\rightarrow f(24) = \frac{1}{4}( 16)\\\\\rightarrow\boxed{f(24)=4}

⸻⸻⸻⸻

»»————- ★ ————-««  

Hope this helps you. I apologize if it’s incorrect.  

8 0
3 years ago
Read 2 more answers
Analyze the diagram below and complete the instructions that follow.
Mnenie [13.5K]

Answer:

  D.  157°

Step-by-step explanation:

∠EFB and ∠AFB form a linear pair, so are supplementary.

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∠EFB = 157°

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3 years ago
I have no idea how to know when to factor or know when the polynomial is completely factored or not. PLEASE HELP!
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Problem 1 is fully factored as each term is a binomial raised to some exponent. If the exponent isn't showing up, it's because it is 1. Recall that x^1 = x.

Problem 2 can be factored further because x^2-8x+16 factors to (x-4)(x-4) or (x-4)^2. To get this factorization, you find two numbers that multiply to 16 and add to -8. Those two numbers are -4 and -4 which is where the (x-4)(x-4) comes from. Overall, the entire thing factors to (x-4)^2*(x+3)*(x-2)

Problem 3 is a similar story. We can factor x^2-1 into (x-1)(x+1). I used the difference of squares rule here. Or you can think of x^2-1 as x^2+0x-1, then find two numbers that multiply to -1 and add to 0. Those two numbers are +1 and -1 which leads to (x+1)(x-1). So the full factorization is (x-1)(x+1)(x+1)(x-4) which is the same as (x-1)(x+1)^2(x-4)

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