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Talja [164]
3 years ago
11

A line passes through the point (-3, -3) and has a slope of 1/2 What is the equation of the line?

Mathematics
1 answer:
masya89 [10]3 years ago
3 0
Y-y1=m(x-x1)
(x1,y1) is a given point
m=slope
y-(-3)=1/2(x-(-3))
y+3=1/2(x+3) is an equation



2x+3y=6
x+y=4
multiply second equation by -2 and add to first

2x+3y=6
<u>-2x-2y=-8 +</u>
0x+1y=-2

y=-2
sub back

x+y=4
x-2=4
add 2
x=6

x=6
y=-2
(6,-2)
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Adult tickets for the game cost $4 each and student tickets cost $3 each. A total of 105 tickets worth $380 were sold. How many
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Answer:

There were 40 student tickets sold.

Step-by-step explanation:

First I set up equations to represent this situation.

4x+3y=380

x+y=105

x represents the adult tickets and y represents the student tickets.

I can solve this with the elimination method. I want to cancel out the x so I will multiply every term in equation 2 by -4.

4x+3y=380

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Now I combine like terms.

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erastova [34]

Answer:

7. x = -2 +/- 4i\sqrt{5}

8. x = 2 or x = 6

9. x = -2 +/- \frac{\sqrt{26} }{2} i

10. t = -3 +/- \sqrt{35}

Step-by-step explanation:

7. Subtract 320 from both sides: 4(x + 2)^2 = -320

Divide by 4: (x + 2)^2 = -80

Square root both sides: x + 2 = +/- \sqrt{-80}. We need to add the imaginary i to this: +/- \sqrt{-80} = +/- i\sqrt{80} = +/- 4i\sqrt{5}

Subtract 2 from both sides: x = -2 +/- 4i\sqrt{5}

8. Add 18 to both sides: 7(x - 4)^2 = 28

Divide by 7: (x - 4)^2 = 4

Square root both sides: x - 4 = +/- 2

Add 4 to both sides: x = 4 +/- 2  ⇒  x = 2 or x = 6

9. Add 5 to both sides: -2(x + 2)^2 = 13

Divide by -2: (x + 2)^2 = -13/2

Square root both sides: x + 2 = +/- \sqrt{-13/2}. We again need i: +/- \sqrt{-13/2} = +/- i\sqrt{13/2} = +/- \frac{\sqrt{26} }{2} i

Subtract 2 from both sides: x = -2 +/- \frac{\sqrt{26} }{2} i

10. Multiply by 5 on both sides: (t + 3)^2 = 35

Square root both sides: t + 3 = +/- \sqrt{35}

Subtract 3: t = -3 +/- \sqrt{35}

Hope this helps!

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