A line passes through the point (-3, -3) and has a slope of 1/2 What is the equation of the line?

1 answer:

3 0

Y-y1=m(x-x1)
(x1,y1) is a given point
m=slope
y-(-3)=1/2(x-(-3))
y+3=1/2(x+3) is an equation

2x+3y=6
x+y=4
multiply second equation by -2 and add to first

2x+3y=6
-2x-2y=-8 +
0x+1y=-2

y=-2
sub back

x+y=4
x-2=4
add 2
x=6

x=6
y=-2
(6,-2)

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Substitution:

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Answer:

The equation of the straight line in point - slope form

y +1 = -2 ( x-2)

Step-by-step explanation:

Step(i):-

Given points are C( 2,-1) and D(1,1)

Slope of the line

$m = \frac{y_{2}-y_{1} }{x_{2}-x_{1} } = \frac{1-(-1)}{1-2} = \frac{2}{-1} = -2$

m = -2

Step(ii):-

Equation of the straight line passing through the point ( 2,-1) and having slope

m =-2

y - y₁ = m ( x- x₁)

y - (-1) = -2 ( x-2)

y +1 = -2 ( x-2)

Final answer:-

The equation of the straight line

y +1 = -2 ( x-2)

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