A line passes through the point (-3, -3) and has a slope of 1/2 What is the equation of the line?
1 answer:
Y-y1=m(x-x1)
(x1,y1) is a given point
m=slope
y-(-3)=1/2(x-(-3))
y+3=1/2(x+3) is an equation
2x+3y=6
x+y=4
multiply second equation by -2 and add to first
2x+3y=6
<u>-2x-2y=-8 +</u>
0x+1y=-2
y=-2
sub back
x+y=4
x-2=4
add 2
x=6
x=6
y=-2
(6,-2)
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