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Yanka [14]
3 years ago
12

Can someone help me do this. -unnecessary comments will be reported

Mathematics
1 answer:
qaws [65]3 years ago
7 0
The answer would be 36
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john has earnes a 77, 76 and a 84 on his first three projects of the semester.if he hopes to have a b average (80 or above) what
lukranit [14]
He need to have at least an 83
8 0
2 years ago
X = (y + 3) / 12 solve for y
slega [8]

Answer:

y = 12x-3

Step-by-step explanation:

X = (y + 3) / 12

Multiply each side by 12 to clear the fraction

12 x = (y+3)/12 *12

12x = y+3

Subtract 3 from each side

12x -3 = y+3-3

12x-3 =y

8 0
3 years ago
Need help with this
Marrrta [24]

Answer:

law of cosines states c^2=a^2+b^2-2abc

b^2=26^2+24^2-2(26×24)cos 134°

b^2=676+576-1248cos134°

cos134= -0.6946

b^2=1252-12(-0.6946)

12×(-0.6946)= -8.3352

b^2=1252-(-8.3352)

b^2=1252+8.3352

b^2=1260.33

b=√1260.33

b=35.50

7 0
2 years ago
Find the missing factor BBB that makes the equality true. -35x^6=(-5x^2)(B)−35x 6 =(−5x 2 )(B)minus, 35, x, start superscript, 6
Sveta_85 [38]

Answer:

B=7x^4

Step-by-step explanation:

The given equality is

-35x^6=(-5x^2)B

Take the term (-5x^2) to the left hand side. This means the term -35x^6 will be divided by (-5x^2)

\dfrac{-35x^6}{(-5x^2)}=B

Now since both the numerator and denominator have negative sign the value of fraction will be positive.

\dfrac{35x^6}{(5x^2)}=B

Now 5\times 7=35 and x^{6-2}=x^4

7x^4=B

So, the missing factor B=7x^4

4 0
2 years ago
What would be the steps to solving this problem?<br><br> <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D" id="TexFormula
lidiya [134]
Isolate the variable by dividing each side by factors that don’t contain the variable.

X = -2

Hope this helps!
Have a great day!
3 0
2 years ago
Read 2 more answers
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