HELLLLLLLLLLLLLLLLLLLLP 100 points, please really help me
1 answer:
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Answer:
The frequency distribution is
The frequency distribution is
S/N Class limit Frequency
1 0-2 4
2 3 -4 1
3 5-6 2
4 7-8 2
5 9 - 10 0
6 11 - 12 0
The value for value upper class boundary of the fifth class is
Step-by-step explanation:
From the question we are told that
The lower class limit is 0
The class width is 2
The scores is 8,6,2,4,2,0,2,6,7
The frequency distribution is
S/N Class limit Frequency
1 0-2 4
2 3 -4 1
3 5-6 2
4 7-8 2
5 9 - 10 0
6 11 - 12 0
Generally the upper class boundary of the fifth class is mathematically represented as
ANSWER
EXPLANATION
It was given that ∆CDE is an isosceles triangle.
The length of the sides are given in terms of x as follows.
It was also given that, angle D is congruent to angle E.
This implies that, side CD and CE are equal.
Thus,
In terms of x, we have;
We group like terms to get,
Divide both sides by 12 to get,
The length of the sides are;
EXPLANATION
It was given that ∆CDE is an isosceles triangle.
The length of the sides are given in terms of x as follows.
It was also given that, angle D is congruent to angle E.
This implies that, side CD and CE are equal.
Thus,
In terms of x, we have;
We group like terms to get,
Divide both sides by 12 to get,
The length of the sides are;