Hi there
The formula is
A=p (1+r/k)^kt
A future value 3000
P present value 100
R interest rate 0.02
K compounded monthly 12
T time?
We need to solve for t
T=[log (A/p)÷log (1+r/k)]÷k
T=(log(3,000÷100)÷log(1+0.02÷12))÷12
T=170.202 years
So it's a
Hope it helps
Answer: i cant see the pic i would help but i cant see picture
Step-by-step explanation:
20^2 + 21^2 = 27^2
400 + 441 = 729
881 = 729 (does not equal)
Not a right traingle
Answer:
(364.595 ; 391.405)
Step-by-step explanation:
Given the sample data:
406, 385, 389, 383, 352, 379, 388, 343, 368, 387
Using calculator :
Sample mean, xbar = 378
Standard deviation, s = 18.74
Confidence interval :
Xbar ± Margin of error
Margin of Error = Tcritical * s/√n
TCritical at df = 24 ; 0.05 = 2.262
Margin of Error = 2.262 * 18.74/√10 = 13.405
Lower boundary = (378 - 13.405) = 364.595
Upper boundary = (378 + 13.405) = 391.405
(364.595 ; 391.405)
