The net charge of pantothenate is -1 whereas the net charge of phosphopantothenate is −2 in aqueous solution at pH 7.
<h3>What is the net charge of both pantothenate and phosphopantothenate?</h3>
At pH 7, the carboxylic acid of pantothenate will lose one hydrogen ion which leads to a net charge of −1 on pantothenate while on the other hand, the phosphate group of phosphopantothenate will lose two hydrogen ions (−2) so −2 charge appear on the phosphopantothenate.
So we can conclude that The net charge of pantothenate is -1 whereas the net charge of phosphopantothenate is −2 in aqueous solution at pH 7.
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It would be "Double replacement".
Hope this helps!
Answer:
Momentum, p = 34.937 kg-m/s
Explanation:
It is given that,
Force acting on the bowling ball, F = 48.2 N
Velocity of bowling ball, v = 7.13 m/s
We have to find the momentum of the ball. Momentum is given by :
p = mv........(1)
Firstly, calculating the mass of bowling ball using second law of motion. The force acting on the ball is gravitational force and it is given by :
F = m g (a = g)


m = 4.9 kg
Now putting the value of m in equation (1) as :

p = 34.937 kg-m/s
Hence, this is the required solution.
linear charge density of system of two line charges is given as

now as we know that electric field due to a line charge at some distance from it is given by

so here we will first find the electric field of first line charge at the position of other line charge


now as we know that

here q = charge on the line charge system at which force is required
E = electric field on that system of charge where force is required
now we can find the charge by


Now using the above formula



so force on the part of wire is F = 0.0811 N
The correct option is B.
There were 4 treatment conditions compared in the experiment.
F ratio plays an essential role in performing a particular dataset of ANOVA. F ratio is particularly a ratio which is obtained by the between-group variance or it is also called MSB and also within-group variance known as MSW. Any F-ratio which is computed is compared with the critical F-ratios from the table as it will check out if there are any variations available between the groups or not.
The researcher reports an F-ratio where the degrees of freedom = 3, 36.
F-ratio is obtained by the calculation of dividing the Mean squared errors because of the treatment by the Mean squared error which occurs due to error.
For the particular case, the researcher reports an F-ratio having degrees of freedom = 3, 36. It is indicating that the treatments are being distributed with degrees of freedom which is 3 and specified errors are distributed with degrees of freedom which is 36.
Let the treatments which were involved in the study can be denoted by k.
Let the total number of individuals involved in the study can be taken as N.
Then, the treatments will be having degrees of freedom as,
= k-1
3=k-1
k=3+1=4
Therefore, the required treatment condition number that was compared is 4.
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