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elena-14-01-66 [18.8K]

2 years ago

10

The term _____ of energy means that the total amount of energy at the start and end of an energy transformation must be the same

.
A. transfer
B. releasing
C. production
D. conservation

1 answer:

Mnenie [13.5K]2 years ago

8 0

I think is conversation

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What is the primary function of a landfill?

RSB [31]

The most important function of a landfill is to store and get rid of solid waste which it provides an area where waste is disposed of and can be managed properly in order to reduce health and environmental risk<span />

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3 years ago

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A sinusoidal, transverse wave that propagates in the positive x-direction can be described with the wave function y of xt is equ

myrzilka [38]

Answer:

$\omega =\frac{2 \pi }{T}$ rad/s

Explanation:

The wave function is:

$y(xt) = Acos(kx- \omega t)$

where :

k = wave number

x = position of a point on the wave

$\omega$ = angular frequency

t = time

What is another way to express the angular frequency (omega)

Angular frequency (omega) can be express as :

$\omega =\frac{2 \pi }{T}$ rad/s ( i.e one repetition that it takes to repeats itself)

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2 years ago

A force F = (2.75 N)i + (7.50 N)j + (6.75 N)k acts on a 2.00 kg mobile object that moves from an initial position of d = (2.75 m

Natasha2012 [34]

Answer:

The work done on the object by the force in the 5.60 s interval is 40.93 J.

Explanation:

Given that,

Force $F=(2.75\ N)i+(7.50\ N)j+(6.75\ N)k$

Mass of object = 2.00 kg

Initial position $d=(2.75)i-(2.00)j+(5.00)k$

Final position $d=-(5.00)i+(4.50)j+(7.00)k$

Time = 4.00 sec

We need to calculate the work done on the object by the force in the 5.60 s interval.

Using formula of work done

$W=F\cdot d$

$W=F\cdot(d_{f}-d_{i})$

Put the value into the formula

$W=(2.75)i+(7.50)j+(6.75)k\cdot (-(5.00)i+(4.50)j+(7.00)k-(2.75)i+(2.00)j-(5.00)k)$

$W=(2.75)i+(7.50)j+(6.75)k\cdot((-7.75)i+6.50j+2.00k)$

$W=2.75\times-7.75+7.50\times6.50+6.75\times2.00$

$W=40.93\ J$

Hence, The work done on the object by the force in the 5.60 s interval is 40.93 J.

4 0

2 years ago

Problem: An ice hockey player hits a puck of mass 0.15 kilograms with a force of 100 newtons in the horizontal direction. What i

valina [46]

The acceleration produced in a body is always in the direction of the resultant force acting on the body. Therefore, we may determine the horizontal acceleration using the horizontal force applied. To do this, we may apply the mathematical form of Newton's second law:

Force = mass * acceleration
acceleration = force / mass

Substituting the values,
a = 100 / 0.15
a = 666.7 m/s²

The acceleration of the hockey puck is 670 m/s²

7 0

3 years ago

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Mercury is a liquid metal having a density of 13.6 g/mL. What is the

sergij07 [2.7K]

Answer:

$\boxed {\boxed {\sf v \approx 33.088 \ mL}}$

Explanation:

The formula for density is:

$d= \frac{m}{v}$

where <em>m</em> is the mass and <em>v</em> is the volume.

The mass is 0.45 kilograms and the density is 13.6 grams per milliliter. The density is given in grams, so we must convert the mass.

There are 1000 grams in 1 kilogram or $\frac{1000 \ g} {1 \ kg}$ . We can multiply the mass by this ratio.

$0.45 \ kg * \frac{1000 \ g} {1 \ kg} = 0.45 * 1000 \ g = 450 \ g$

Now we have values for the mass and density:

$13.6 \ g/mL =\frac{450 \ g}{ v}$

Cross multiply.

$\frac {13.6 \ g/mL}{1} =\frac{450 \ g}{ v}$

$13.6 \ g/mL * v=450 \ g * 1 \\13.6 \ g/mL * v=450 \ g$

We are trying to find the volume, so we must isolate that variable.

13.6 and v are being multiplied. The inverse of multiplication is division. Divide both sides by 13.6

$\frac {13.6 \ g/mL*v } { 13.6 \ g/mL} = \frac{ 450 \ g} {13.6 \ g/mL}$

$v= \frac{ 450 \ g} {13.6 \ g/mL}$

The grams will cancel.

$v= 33.0882353 \ mL\\v \approx 33.088 \ mL$

The volume is about 33.088 milliliters.

3 0

2 years ago