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xenn [34]
3 years ago
7

10) What is the area of the figure below? Round your answer to the nearest tenth (1 place

Mathematics
1 answer:
Furkat [3]3 years ago
3 0
75 units squared. separate the shapes into a rectangle and triangle, find the area of each, and add together
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Find the values of x and y using trig
Natasha_Volkova [10]

Answer:

Step-by-step explanation:

The triangle is a right angle triangle. This is because one of its angles is 90 degrees.

Let us determine x

Taking 47 degrees as the reference angle,

x = adjacent side

11 = hypotenuse

Applying trigonometric ratio,

Cos # = adjacent side / hypotenuse

# = 47 degrees

Cos 47 = x/11

x = 11cos47

x = 11 × 0.6820

x = 7.502

Let us determine y

Taking 47 degrees as the reference angle,

y = opposite side

11 = hypotenuse

Applying trigonometric ratio,

Sin # = opposite side / hypotenuse

# = 47 degrees

Sin 47 = y/11

x = 11Sin47

x = 11 × 0.7314

x = 8.0454

7 0
3 years ago
Write an inequality for the sentence. <br><br> c is not less than zero.
Zepler [3.9K]

c  \leqslant 0
6 0
3 years ago
two mountain bikers leave from the same parking lot and head in opposite directions on two different trails. the first rider goe
sveta [45]

Applying the required <em>rule </em>or <em>theorem</em>, it can be concluded that the second biker is <u>farther</u> from the <em>parking lot</em>. The distance of the bikers to the <em>parking lot</em> are:

i. First biker = 17.0 km

ii. Second biker = 20.22 km

The <u>path</u> of travel of both bikers would form a triangle. Applying the <u>Pythagoras</u> theorem to the path of the <em>first</em> biker would give his <u>distance</u> from the starting point. While applying the <u>cosine</u> rule to the path of <em>second</em> rider would gives his <u>distance</u> to the starting point.

Thus,

a. <u>To determine the distance of the first biker from the parking lot.</u>

Let the required <em>distance </em>be represented by x. Applying the Pythagoras theorem, we have:

hyp^{2} = adj 1^{2} + adj 2^{2}

x^{2} = 8^{2} + 15^{2}

   = 64 + 225

   = 289

x = \sqrt{289}

  = 17

x = 17 km

Thus, the <u>first</u> biker is 17.0 km from the <em>starting</em> point.

b. <u>To determine the distance of the second biker from the parking lot.</u>

Let the required <em>distance</em> be represented by x. So that applying the cosine rule, we have:

c^{2} = a^{2} + b^{2} - 2ab Cos θ

x^{2} = 8^{2} + 15^{2} - 2(15*8) Cos (180 - 20)

    = 64 + 225 - 240 Cos 160

    = 289 - 240 * -0.5

x^{2} = 289 + 120

   = 409

x = \sqrt{409}

 = 20.2237

x = 20.22 km

Thus, the <u>second</u> biker is 20.22 km from the <em>starting</em> point.

Therefore, the second biker is <u>farther</u> from the <em>parking lot</em>.

A sketch of the path of travel for the two bikers is attached for more clarifications.

Visit: brainly.com/question/22699651

7 0
2 years ago
If hugo goes out for dinner and pays 2$ of sales tax on a 20$ meal what percentage is the sales tax in his city?
vesna_86 [32]
<h3>Answer:  10%</h3>

Work Shown:

2/20 = 0.10 = 10%

Note that 10% of 20 = 0.10*20 = 2 dollars is the sales tax to help confirm the answer.

8 0
3 years ago
Find the y-intercept and the x-intercept of the line 2x-4y=10
kompoz [17]
Finding y intercept and x intercept is easy:

X intercept will be of the form (x,0) and y intercept will be of the form (0,y)

● If you put x=0 in the equation, you will get y-intercept.

● If you put y=0 in the equation, you will get x-intercept.
______________________________

Given equation: 2x - 4y = 10

◆ Put x = 0
2×0 - 4y = 10
=> -4y = 10
=> y = 10/(-4)
=> y = -5/2

Thus y intercept is (0, -5/2)

◆Put y = 0
2x - 4×0 = 10
=> 2x = 10
=> x = 10/2
=> x = 5

Thus the x intercept is (5,0)
4 0
3 years ago
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