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Lena [83]
3 years ago
6

Dr. Jones is having his Introductory to Criminal Justice students analyze cartoons. He instructs them to identify the number of

violent acts per show, the type of violent act and the characteristics of the victim. Dr. Jones is having his students use:
- content analysis
- secondary data
- new data collected by agency staff
- nonpublic agency records
Mathematics
1 answer:
ivolga24 [154]3 years ago
8 0

Answer:

The correct option is - content analysis

Step-by-step explanation:

Dr. Jones is having his students use: content analysis.

Content analysis is a type of research technique, where we make similar and valid inferences by coding and interpreting information in text forms.

Here Dr. Jones is asking his students to gather information to identify the violent acts in each cartoon show. So, the students will be gathering content or information and then they will come to some inference.

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A piece of cardboard is 15 inches by 30 inches. A square is to be cut from each corner and the sides folded up to make an open-t
solmaris [256]

Answer:

Maximum volume = 649.519 cubic inches

Step-by-step explanation:

A rectangular piece of cardboard of side 15 inches by 30 inches is cut in such that a square is cut from each corner. Let x be the side of this square cut. When it was folded to make the box the height of box becomes x, length becomes (30-2x) and the width becomes (15-2x).

Volume is given by  

V = V = Length\times Width\times Height\\V = (30 - 2x)(15-2x)x= 4x^3-90x^2+450x\\So,\\V(x) = 4x^3-90x^2+450x

First, we differentiate V(x) with respect to x, to get,

\frac{d(V(x))}{dx} = \frac{d(4x^3-12x^2+9x)}{dx} = 12x^2 - 180x +450

Equating the first derivative to zero, we get,

\frac{d(V(x))}{dx} = 0\\\\12x^2 - 180x +450 = 0

Solving, with the help of quadratic formula, we get,

x = \displaystyle\frac{5(3+\sqrt{3})}{2}, \frac{5(3-\sqrt{3})}{2},

Again differentiation V(x), with respect to x, we get,

\frac{d^2(V(x))}{dx^2} = 24x - 180

At x =

\displaystyle\frac{5(3-\sqrt{3})}{2},

\frac{d^2(V(x))}{dx^2} < 0

Thus, by double derivative test, the maxima occurs at

x = \displaystyle\frac{5(3-\sqrt{3})}{2} for V(x).

Thus, largest volume the box can have occurs when x = \displaystyle\frac{5(3-\sqrt{3})}{2}}.

Maximum volume =

V(\displaystyle\frac{5(3-\sqrt{3})}{2}) = (30 - 2x)(15-2x)x = 649.5191\text{ cubic inches}

8 0
3 years ago
Find an equation of the line containing (-3,4) and having slope -2. If this line contains the points (a,8) and (5,b), find a and
larisa [96]

Answer:

Step-by-step explanation:

Remark

The slope intercept line is written as y = mx + b in it's general form.

You can get the slope, m, immediately because it is given as -2

So far what you have is y = -2x + b

y intercept

To get the y intercept, use the point (-3 , 4)

x = - 3

y = 4

4 = -2*(-3) + b

4 = 6 + b                 Subtract 6 from both sides

4 - 6 = 6-6 + b

b = - 2

Line

y = -2x - 2

(a,8)

y = -2a - 2

8 = -2a - 2              Add 2 to both sides

8 +2 = -2a -2+2     Combine

10 = - 2a                 Divide by - 2

10/-2 = a

a = -5

(5,b)

y = -2x - 2

x = 5

y = b

b = -2*5 - 2

b = -10 - 2

b = - 12

6 0
2 years ago
Cindy has a savings account with $7,500 in it that earns 7% simple interest per year.
WINSTONCH [101]

Answer:

The interest is $1050 and the amount is $8550.

Step-by-step explanation:

8 0
3 years ago
Which fraction is the bigger fractured 2/10 or 23/100
lesantik [10]
Answer: 23/100

Find the greatest common factor (gcf)

Which is 100 so 23/100 is done

2/10 multiply 10 times 10 to get 100

Multiply 2 times 10 which is 20/100

23/100 is greater
4 0
3 years ago
Read 2 more answers
I NEED THIS ASAP! PLEASE HELP! Part A: Explain why the x-coordinates of the points where the graphs of the equations y = 4-X and
Natali5045456 [20]

Answer:

A.  We have two lines:  y = 2-x   and   y = 4x+3 Given two simultaneous equations that are both required to be true.. the solution is the points where the lines cross...  Which is where the two equations are equal..  Thus the solution that works for both equations is when 2-x = 4x+3 because where that is true is where the two lines will cross and that is the common point that satisfies both equations.   B.  2-x = 4x+3   x     2-x      4x+3

______________

-3     5       -9

-2     4       -5

-1     3       -1

0     2        3

1     1        7

2     0      11

3    -1      15

The table shows that none of the integers from [-3,3] work because in no case does

2-x = 4x+3   To find the solution we need to rearrange the equation to the form x=n 2-x = 4x+3 2 -x + x = 4x + x +3 2 = 5x + 3 2-3 = 5x +3-3 5x = -1 x = -1/5   The only point that satisfies both equations is where x = -1/5 Find y:   y = 2-x  = 2 - (-1/5) = 2 + 1/5 = 10/5 + 1/5 = 11/5 Verify we get the same in the other equation y = 4x + 3   =  4(-1/5) + 3 = -4/5 + 15/5 = 11/5   Thus the only actual solution, being the point where the lines cross, is the point (-1/5, 11/5)   C.  To solve graphically  2-x=4x+3 we would graph both lines...   y = 2-x  and   y = 4x+3 The point on the graph where the lines cross is the solution to the system of equations ... [It should be, as shown above, the point (-1/5, 11/5)]   To graph y = 2-x   make a table.... We have already done this in part B   x     2-x                x    4x+3 _______              ________ -1    3                   -1      -1  0    2                    0       3  1    1                    1       7   Just graph the points on a cartesian coordinate system and draw the two lines.  The solution is, as stated, the point where the two lines cross on the graph.  

Hope this helps.

Step-by-step explanation:

3 0
3 years ago
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