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3 years ago

What is the answer to 3/x=-3/3x+5

Mathematics

1 answer:

Aleonysh [2.5K]3 years ago

7 0

Answer:

$-\frac{5}{4} =x$

Step-by-step explanation:

We first need to bring x up into the numerator. I will find common denominators by multiplying both sides by each denominator.

$\frac{x(3x+5)}{1} *\frac{3}{x} =\frac{-3}{3x+5}*\frac{x(3x+5)}{1}$

This will eliminate both denominators and leave me with

$(3x+5)3=-3(x)\\9x+15=-3x$ after I simplify the parenthesis.

Now I will solve the equation for x by subtracting 9x from both sides.

$9x-9x+15=-3x-9x\\15=-12x$

Then divide by the coefficient of x.

$\frac{15}{-12}=\frac{-12x}{-12}$

$-\frac{5}{4} =x$

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Let the probability of success on a Bernoulli trial be 0.26. a. In five Bernoulli trials, what is the probability that there wil

andreyandreev [35.5K]

Answer:

0.3898 = 38.98% probability that there will be 4 failures

Step-by-step explanation:

A sequence of Bernoulli trials forms the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Let the probability of success on a Bernoulli trial be 0.26.

This means that $p = 0.26$

a. In five Bernoulli trials, what is the probability that there will be 4 failures?

Five trials means that $n = 5$

4 failures, so 1 success, and we have to find P(X = 1).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{5,1}.(0.26)^{1}.(0.74)^{4} = 0.3898$

0.3898 = 38.98% probability that there will be 4 failures

4 0

3 years ago

Help please thanks so much

suter [353]

Answer:

4/6 0r 2/3

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Rex took out a loan for $5000 and planned to pay it back in 4 years. If he paid $600 in interest for those 4 years, what was the

Gwar [14]

$~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill & \$600\\ P=\textit{original amount deposited}\dotfill & \$5000\\ r=rate\to r\%\to \frac{r}{100}\\ t=years\dotfill &4 \end{cases} \\\\\\ 600=5000(\frac{r}{100})(4)\implies \cfrac{600}{5000(4)}=\cfrac{r}{100}\implies \cfrac{3}{100}=\cfrac{r}{100}\implies \boxed{3=r}$