What is the answer to 3/x=-3/3x+5

Mathematics

1 answer:

Aleonysh [2.5K]3 years ago

7 0

Answer:

$-\frac{5}{4} =x$

Step-by-step explanation:

We first need to bring x up into the numerator. I will find common denominators by multiplying both sides by each denominator.

$\frac{x(3x+5)}{1} *\frac{3}{x} =\frac{-3}{3x+5}*\frac{x(3x+5)}{1}$

This will eliminate both denominators and leave me with

$(3x+5)3=-3(x)\\9x+15=-3x$ after I simplify the parenthesis.

Now I will solve the equation for x by subtracting 9x from both sides.

$9x-9x+15=-3x-9x\\15=-12x$

Then divide by the coefficient of x.

$\frac{15}{-12}=\frac{-12x}{-12}$

$-\frac{5}{4} =x$

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a car rental company charges $30 per day to rent a car plus $0.02 per mile driven. which equation represents c, the total cost t

Virty [35]

Answer:

c=0.02(m)+30(5)

c= 150+0.02(m)

c=0.02(m)+150

c=30(5)+0.02(m)

Step-by-step explanation:

This is because c, or cost is equal to 30 dollars a day as a base fee or 150 total for five days plus 0.02 per mile. So, if you multiple the mileage driven by 0.02 and add 150 for the 30$ per day at 5 days. This is your equation

These are just different ways you could write that since it is clear you have a multiple choice question

7 0

3 years ago

A community theater uses the function p (d) = (-4d+40) (d−40) to model the profit (in dollars) expected in a weekend when the ti

fomenos

The theater make the maximum profit at d = $25. Then the maximum profit of the theatre is $ 900.

<h3>What is differentiation?</h3>

The rate of change of a function with respect to the variable is called differentiation. It may be increasing or decreasing.

A community theater uses the function P(d) = (− 4d + 40) (d − 40) to model the profit (in dollars) expected on a weekend when the tickets to a comedy show are priced at d dollars each.

Then the maximum profit of the theatre will be

The function is P(d) = (− 4d + 40) (d − 40)

Differentiate the function with respect to d and put it equal to zero for maximum or minimum profit.

$\begin{aligned} \dfrac{\mathrm{d} }{\mathrm{d} d}P(d) &= 0\\\\\dfrac{\mathrm{d} }{\mathrm{d} d}(- 4d + 40) (d - 40) &= 0\\\\(-4d+40) -4 (d-40) &= 0\\\\-8d + 200 &= 0\\\\d &= 25 \end{aligned}$

Then the checking for maximum or minimum, again differentiate, we have

$\begin{aligned} \dfrac{\mathrm{d} }{\mathrm{d} d}P(d) &= \dfrac{\mathrm{d} }{\mathrm{d} d}(- 4d + 40) (d - 40) \\\\\dfrac{\mathrm{d} }{\mathrm{d} d}P(d) &= \dfrac{\mathrm{d} }{\mathrm{d} d}(-8d + 200) \\\\\dfrac{\mathrm{d} }{\mathrm{d} d}P(d) &= -8\\\\ \dfrac{\mathrm{d} }{\mathrm{d} d}P(d) & < 0\end{aligned}$