Simplify the expression.

Mathematics

1 answer:

Dmitriy789 [7]2 years ago

4 0

Answer:

when you distrbe you get x^2 y

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You’ve explored a variety of trigonometric applications and studied different coordinate systems in the process, namely the Cart

Vaselesa [24]

Answer:

Step-by-step explanation:

this idea is probably a good thing to have a solid understand of. That Cartesian (rect) is the x and y components, of the legs of a triangle and is a way to measure that part of the two leg of the triangle that is made up by those pieces.. while the polar system would measure the hypotenuse of that same triangle with the degrees as a way to place where that hypotenuses goes

the abs value of an imaginary number will give you that distance from the origin to the point.. if you are using that sqrt ( $x^{2}$ + $y^{2}$ ) to get the abs. this is the same as the magnitude and can represent a total force. The distance between the origin and the point is that idea of two points.. conveniently we used (0,0) the origin as one of the points.. the other is at the top of the line or the point given by the complex number

Hopefully that helps... :/

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2 years ago

F(x) = (x - 2)^2 + 2<br> find the range of the function

a_sh-v [17]

Vertex = (2, 2)
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2 years ago

Greetings. As a beginner, I'm struggling a bit to learn calculus. May I know what is the derivative of x to the power 4 step by

elena-14-01-66 [18.8K]

If you're just starting calculus, perhaps you're asking about using the definition of the derivative to differentiate $x^4$ .

We have

$\dfrac{d}{dx} x^4 = \displaystyle \lim_{h\to0} \frac{(x+h)^4 - x^4}h$

Expand the numerator using the binomial theorem, then simplify and compute the limit.

$\dfrac{d}{dx} x^4 = \displaystyle \lim_{h\to0} \frac{(x^4+4hx^3 + 6h^2x^2 + 4h^3x + h^4) - x^4}h \\\\ ~~~~~~~~ = \lim_{h\to0} \frac{4hx^3 + 6h^2x^2 + 4h^3x + h^4}h \\\\ ~~~~~~~~ = \lim_{h\to0} (4x^3 + 6hx^2 + 4h^2x + h^3) = \boxed{4x^3}$

In general, the derivative of a power function $f(x) = x^n$ is $\frac{df}{dx} = nx^{n-1}$ . (This is the aptly-named "power rule" for differentiation.)