3 years ago

At higher temperatures, air can hold __vapor as compared to air at lower?

Chemistry

1 answer:

Veronika [31]3 years ago

7 0

Answer:

water vapor

Explanation:

the the answer is water vapor

You might be interested in

of the following warnings, which one refers to a chemical property of a substance? fragile flammable handle with care shake well

coldgirl [10]

Flammable is ur answer

6 0

4 years ago

ObIel WiLll unt COl.. USSMS A certain chemical reaction releases 31.2 kJ/g of heat for each gram of reactant consumed. How can y

aleksandr82 [10.1K]

Answer:

The expression to calculate the mass of the reactant is $m = \frac{1.080kJ}{31.2kJ/g}$

Explanation:

The amount of heat released is equal to the amount of heat released per gram of reactant times the mass of the reactant. To keep to coherence between units we need to transform 1,080 J to kJ. We do so with proportions:

$1,080J.\frac{1kJ}{10^{3}J } =1.080kJ$

Then,

$1.080kJ=31.2\frac{kJ}{g} .m\\m = \frac{1.080kJ}{31.2kJ/g}$

5 0

4 years ago

Read 2 more answers

What is 316 Kelvin in Celsius ?

ss7ja [257]

Answer:

42.85 Celsius

5 0

3 years ago

In general, ionization energy will?

bija089 [108]

increase while moving left to right within a period and increase while moving upward within a group.

3 0

3 years ago

Read 2 more answers

The reaction 2a → a2 was experimentally determined to be second order with a rate constant, k, equal to 0.0265 m–1min–1. if

katovenus [111]

The integrated rate law for a second-order reaction is given by:

$\frac{1}{[A]t} = \frac{1}{[A]0} + kt$

where, [A]t= the concentration of A at time t,

[A]0= the concentration of A at time t=0

k = the rate constant for the reaction

Given: [A]0= 4 M, k = 0.0265 m–1min–1 and t = 180.0 min

Hence, $\frac{1}{[A]t} = \frac{1}{4} + (0.0265 X 180)$

= 4.858

Therefore, [A]t= 0.2058 M.

Answer: Concentration of A, after 180 min, is 0.2058 M

7 0

3 years ago

Read 2 more answers