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mars1129 [50]
3 years ago
5

Balance the equation. SiO2 + CaC2 → Si + CaO + CO2

Chemistry
1 answer:
Sunny_sXe [5.5K]3 years ago
6 0
Co2 is oxygen because that what you took to ask ppl for
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What is the molarity of a solution containing 23 g of NaCl in 500 mL of solution?
trapecia [35]

molarity of a solution means mols per liter.

First, you need to convert 23 grams on NaCl into mols. 23g divided by molar mass (58.44g/mol) which gives you .394 mols.

Now, you need to convert 500ml to L which moves the decimal three places to the left, giving you .500L of solution.

Finally, divide the mols over solution to get .787M

7 0
3 years ago
Give reason brick is a solid
Elenna [48]
The brick is solid because it's not hollow or containing spaces or gaps
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How is a crystal different from a solid made of individual molecules
Dmitry [639]
In a crystal, the molecules are closer together as they are in any solid. they have less room to move, and might even be combined together rather than individual

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3 years ago
Given the reaction: A + B <--> C + D
Lady_Fox [76]

Answer:

A.) 4.0

Explanation:

The general equilibrium expression looks like this:

K = \frac{[C]^{c} [D]^{d} }{[A]^{a} [B]^{b} }

In this expression,

-----> K = equilibrium constant

-----> uppercase letters = molarity

-----> lowercase letters = balanced equation coefficients

In this case, the molarity's do not need to be raised to any numbers because the coefficients in the balanced equation are all 1. You can find the constant by plugging the given molarities into the equation and simplifying.

K = \frac{[C]^{c} [D]^{d} }{[A]^{a} [B]^{b} }                                       <----- Equilibrium expression

K = \frac{[2 M] [2 M]}{[1 M] [1 M] }                                     <----- Insert molarities

K = \frac{4}{1  }                                                <----- Multiply

K = 4                                                <----- Divide

6 0
2 years ago
Draw the structure of bromous acid, hbro2. optimize formal charges.
ArbitrLikvidat [17]

STRUCTURE OF BROMOUS ACID: H–O–Br=O

<span>In this structure, all the elements have a formal charge of zero. The formal charge of each element is calculated below: </span><span>

H: 1 – 1/2(2) – 0 = 0
O: 6 – 1/2(4) – 4 = 0
Br: 7 – 1/2(6) – 4 = 0
<span>O: 6 – 1/2(4) – 4 = 0</span></span>

8 0
3 years ago
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