It's quite simple when you break it down
20/45 let's divide by 5
4/9
we can't divide anymore, no common denominator. The answer is 4/9
You need to use a ratio of height (H) to shadow length (L) to solve the first problem. It's basically a use of similar triangles, with two perpendicular sides, and with the shadow making the same angle with the vertical.
6 ft = 72 ins, so that rH/L = 72/16 = 9/2 for the player.
So the bleachers are 9/2 x 6 ft = 27 ft.
For the second problem, 9 ft = 108 in, so that the ratio of the actual linear dimensions to the plan's linear dimensions are 9ft/(1/2in) = 2 x 108 = 216.
So the stage will have dimensions 216 times larger than 1.75" by 3".
That would be 31ft 6ins x 54ft.
Live long and prosper.
Answer:
1. Median
2. Altitude
3. Altitude
4. Neither
Step-by-step explanation:
Median- splits the side into two congruent parts
Altitude- Makes a right angle
1. Splits the side. Median
2. Makes a right angle. Altitude
3. Makes a right angle. Altitude
4. Doesn't make a right angle or split the sides. Neither
Answer:
5.92 times 10 to the 2nd power.
Step-by-step explanation:
So funny I just finished my unit on scientific notation! So what you do is you count the distance from the first non-zero number (in this case, it would be after 5), and count how many places there are until the decimal point. I hope this helped! :D
The answer should be n= -6
