Hi,
Now just divide both sides of equation by -4.
Simplify:
Decimal form:
Hope this helps.
r3t40
9514 1404 393
Answer:
a) E = 6500 -50d
b) 5000 kWh
c) the excess will last only 130 days, not enough for 5 months
Step-by-step explanation:
<u>Given</u>:
starting excess (E): 6500 kWh
usage: 50 kWh/day (d)
<u>Find</u>:
a) E(d)
b) E(30)
c) E(150)
<u>Solution</u>:
a) The exces is linearly decreasing with the number of days, so we have ...
E(d) = 6500 -50d
__
b) After 30 days, the excess remaining is ...
E(30) = 6500 -50(30) = 5000 . . . . kWh after 30 days
__
c) After 150 days, the excess remaining would be ...
E(150) = 6500 -50(150) = 6500 -7500 = -1000 . . . . 150 days is beyond the capacity of the system
The supply is not enough to last for 5 months.
Find the number that when multiplied with 350 will give you 24.5. This number happens to be .07 or in terms of sales tax, 7%.
Answer:
please explain what you meanthank u
Answer:
A
Step-by-step explanation:
x1−9x2−3x1−x2
