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barxatty [35]
3 years ago
14

OmG PLS HELP I am big struggloing

Mathematics
2 answers:
Brilliant_brown [7]3 years ago
7 0

Answer:

b

Step-by-step explanation:

Nataly [62]3 years ago
6 0
Answer is 2,500 so, B
Years. Population
1. 32,500
2. 35,000
3. 37,500
4. 40,000
5. 42,500
6. 45,000

This info is given by graph.
Good luck.
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Find the value of x.
melomori [17]

Answer:

The measure of angle x is 40°

Step-by-step explanation:

we know that

The measurement of the outer angle is the semi-difference of the arcs which comprises

see the attached figure with letters to better understand the problem

so

m∠x=(1/2)[arc AB-arc AC]

<u><em>Find the measure of arc AC</em></u>

we know that

arc AB+arc BC+arc AC=360° ----> by complete circle

substitute the given values

arc AB=200°

arc BC=40°

arc AC=?

200°+40°+arc AC=360°

240°+arc AC=360°

arc AC=360°-240°=120°

<u><em>Find the measure of angle x</em></u>

m∠x=(1/2)[200°-120°]=40°

7 0
3 years ago
If an integer n has three unique prime divisors, then it follows that the largest prime divisor of n is less than or equal to cu
TiliK225 [7]

Answer:

False

Step-by-step explanation:

Lets call the three prime divisors of n p, q, and r, being r the largest, we know:

n=q * p * r

Now, if

q * p < r

then

n < r * r = r^2

So:

\sqrt{n} < \sqrt{r^2} = r

Also, for every natural greater than one, we know:

\sqrt[3]{n}

so

\sqrt[3]{n}

from which:

\sqrt[3]{n} < r

So, we see, this means the preposition is false, we can find a particular counterexample:

q=2

p=3

p*q = 6

We need to choose a prime greater than 6

r=7

n= 2 * 3 *7 = 42

\sqrt[3]{42} = 3.4760 < 7

4 0
4 years ago
Can someone help me plzz​
Wittaler [7]

Answer:3

Step-by-step explanation:

A. 2^4(4n) = 2^48

2^16n = 2^48

16n = 48

n = 3

5 0
3 years ago
Question 5
baherus [9]

9514 1404 393

Answer:

  A. no solution

Step-by-step explanation:

The solution is found where the lines meet. Parallel lines never meet, so there is no solution.

7 0
3 years ago
10
Lerok [7]
Cat in the hat if symmetrical
7 0
3 years ago
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