Answer:
DF= should be 30
Step-by-step explanation:
3 is 4 cause 1x2 is 2 so 1x2 again is 4
Y= -3x+8
y= 3x+2
both points meet at points ( 1 , 5 )
solve algebraically:
-3x+8=3x+2
+3 +3
_________
8=6x + 2
-2 -2
_________
6/6= 6x/6
x=1
y=3(1)+2
y=3+2
y=5
points: (1,5)
9514 1404 393
Answer:
1731 ft
Step-by-step explanation:
The tangent relation is useful in this problem.
Tan = Opposite/Adjacent
The height of the light is found to be ...
tan(11°) = height/(639 ft)
height = (639 ft)·tan(11°) . . . . . solve for height
Then the distance from the light to point B is ...
tan(3°) = height/(B distance)
B distance = height/tan(3°) = (639 ft)·tan(11°)/tan(3°) ≈ 2370 ft
Then the distance from point A to point B is ...
2370 ft -639 ft = 1731 ft . . . AB distance
a−b+c−d−g+2.718282 is the solution for this equation.