3 years ago

Horizontal asymptote

Mathematics

1 answer:

vodomira [7]3 years ago

6 0

Answer:

H.A.=4

Step-by-step explanation:

If the bottom equation is factored, you get (x+1)(x-4)

If the V.A. is -1 ( gotten by putting [x+1] equal to zero I'm guessing) then the H.A. can be gotten by putting (x-4) equal to zero.

Also, I graphed it.

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Elias was given a lock for his school locker. The lock contains numbers between

daser333 [38]

Answer:

34,220

Step-by-step explanation:

Because order doesn't matter, but the numbers can't be repeated, we need to find the number of combinations where 3 individual numbers can be chosen out of 60 possible numbers using the binomial coefficient:

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Thus, Elias can make 34,220 unique 3-number codes given 60 different numbers.

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So sum the prime factors up

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3 years ago

Read 2 more answers

Problem is Sin38-cos52

Paha777 [63]

Notice that 38 and 52 make a total of 90
sinA=cos(90-A)
sin38=cos52, therefore the answer is zero

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3 years ago

Rasek [7]

Answer:

2.6

Step-by-step explanation:

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3 years ago

Factor completely 5x2 − 40.

Tatiana [17]

,Answer:

I got -30

Step-by-step explanation:

Becuase when I did 5 x 2= 10

and 10 -40 = -30

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3 years ago