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a_sh-v [17]
3 years ago
13

Which inequality is represented by this graph?

Mathematics
1 answer:
Mashcka [7]3 years ago
5 0

Answer: C

Step-by-step explanation:

We can say that the equaiton of the line is -1/6x+1, considering that is in each answer choice. Than main part is the shading and inequality. If you look closely at the graph, the shading line is a dashed/dotted line. This means the shaded part does not equal the actual line. We can eliminate B and D.

Now, we are left with A and C. A is saying y< while C is saying y>. C is the correct answer because if you look at the shading, it it above the line, which is greater than. Therefore, the answer is C.

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What is the decimal expansion of 10/11
Novay_Z [31]

Answer:

To write 10/11 as a decimal you have to divide numerator by the denominator of the fraction. We divide now 10 by 11 what we write down as 10/11 and we get 0.90909090909091 And finally we have: 10/11 as a decimal equals 0.90909090909091

Step-by-step explanation:

5 0
2 years ago
Please help<br> Geometry <br> Will give top answer for someone to answer correctly.
Setler79 [48]

Answer:

Length of the minor arc AB = 5.27777777778 cm

Step-by-step explanation:

Here you would require a simple proportionality.

The ratio of the degree of the minor arc (95 degrees) over the total, 360 degrees of every circle, comparative to the length of the minor over the circumference (20 cm).

Here we can propose that the length of the minor can be equal to x.

Now let's substitute the known values:

95 / 360 = x / 20

Now cross multiply:

360 * x = 95 * 20 ⇒

360x = 1900 ⇒

x = 5.27777777778 ⇒

length of the minor arc AB = 5.27777777778 cm

3 0
3 years ago
One of the x-intercepts of the parabola represented by the equation y = 3x^2 + 6x − 10 is approximately (1.08, 0).
Igoryamba
3x^2 + 6x - 10 = 0

x  = [-6 +/- sqrt(^2 - 3*3*-10)] / 2*3

=  1.08 and -3.08

Other x -intercept is (-3.08,0)
4 0
3 years ago
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Consider the curve defined by the equation y=6x2+14x. Set up an integral that represents the length of curve from the point (−2,
torisob [31]

Answer:

32.66 units

Step-by-step explanation:

We are given that

y=6x^2+14x

Point A=(-2,-4) and point B=(1,20)

Differentiate w.r. t x

\frac{dy}{dx}=12x+14

We know that length of curve

s=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}dx

We have a=-2 and b=1

Using the formula

Length of curve=s=\int_{-2}^{1}\sqrt{1+(12x+14)^2}dx

Using substitution method

Substitute t=12x+14

Differentiate w.r t. x

dt=12dx

dx=\frac{1}{12}dt

Length of curve=s=\frac{1}{12}\int_{-2}^{1}\sqrt{1+t^2}dt

We know that

\sqrt{x^2+a^2}dx=\frac{x\sqrt {x^2+a^2}}{2}+\frac{1}{2}\ln(x+\sqrt {x^2+a^2})+C

By using the formula

Length of curve=s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}

Length of curve=s=\frac{1}{12}[\frac{12x+14}{2}\sqrt{1+(12x+14)^2}+\frac{1}{2}ln(12x+14+\sqrt{1+(12x+14)^2})]^{1}_{-2}

Length of curve=s=\frac{1}{12}(\frac{(12+14)\sqrt{1+(26)^2}}{2}+\frac{1}{2}ln(26+\sqrt{1+(26)^2})-\frac{12(-2)+14}{2}\sqrt{1+(-10)^2}-\frac{1}{2}ln(-10+\sqrt{1+(-10)^2})

Length of curve=s=\frac{1}{12}(13\sqrt{677}+\frac{1}{2}ln(26+\sqrt{677})+5\sqrt{101}-\frac{1}{2}ln(-10+\sqrt{101})

Length of curve=s=32.66

5 0
3 years ago
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Darya [45]
The answer to your question is: B
5 0
3 years ago
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