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4 years ago

Which inequality is represented by this graph?

Mathematics

1 answer:

Mashcka [7]4 years ago

5 0

Answer: C

Step-by-step explanation:

We can say that the equaiton of the line is -1/6x+1, considering that is in each answer choice. Than main part is the shading and inequality. If you look closely at the graph, the shading line is a dashed/dotted line. This means the shaded part does not equal the actual line. We can eliminate B and D.

Now, we are left with A and C. A is saying y< while C is saying y>. C is the correct answer because if you look at the shading, it it above the line, which is greater than. Therefore, the answer is C.

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What is the product?

Wewaii [24]

Answer:

-30a^5b + 12a^4b^3 + 16a^3b^2 - 4a^2b^4 - 2 ab^3

Step-by-step explanation:

6 0

2 years ago

Least common multiple of z^2+6z+9 and z^2+z-6

Firdavs [7]

Hint: $\bf \begin{array}{ccllll}
z^2+6z+9&z^2+z-6\\
\downarrow &\downarrow \\
(z+3)(z+3)&\underline{(z+3)(z-2)}
\end{array}$

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3 years ago

Find the future value and interest earned if $8906.54 is invested for 9 years at 6% compounded continuously

dalvyx [7]

To find the future value the formula is
A=p e^rt
A future value?
P present value 8906.54
R interest rate 0.06
T time 9 years
E constant
A=8,906.54×e^(0.06×9)
A=15,283.68

To find the interest earned the formula is
I=A-p
I=15,283.68−8,906.54
I=6,377.14

4 0

3 years ago

Distributions and Comparing Data Project

LenKa [72]

Answer:

1. The shape of the histogram created with MS Excel is approximately bell shaped and approximately evenly spread about the central (largest counts) values

The shape of the box plot created with MS Excel is approximately evenly distributed

2. The appropriate measure of central tendency for a bell shaped histogram is the mean and median, due to the approximately equal distribution about the highest frequency class

3. Part A

The 15 numbers between 1 and 20 generated by a random generator are;

1, 8, 8, 15, 4, 18, 11, 6, 17, 1, 18, 15, 10, 12, 11

The measure of center is the mean = (1+8+8+15+4+18+11+6+17+1+18+15+10+12+11)/15 = 155/15 = 31/3

The measure of spread used is the variance, s² = 32.38

$Where, \,s^2 =\dfrac{\sum \left (x_i-\bar x \right )^{2} }{n - 1}$

${\sum \left (x_i-\bar x \right )^{2} }$ = 453.333

n = 15

s² = 453. $\overline 3$ /(15 - 1) = 32.38

Part B

The measure of central tendency are the mean and the median because the size of the data (n = 15), is 75% of the population (N = 20) nd therefore the data is approximately normal and can be represented by the mean and the standard deviation

Step-by-step explanation:

4 0

3 years ago

What is the average rate of change of f(x) = -x2 + 3x + 6 over the interval –3

Rufina [12.5K]

Answer:

$\frac{\Delta y}{\Delta x} =\frac{f(x_2)-f(x_1)}{x_2-x_1} =\frac{6-(-12)}{3-(-3)} =\frac{18}{6}= 3$

Step-by-step explanation:

To find the average rate of change of a function over a given interval, basically you need to find the slope. The mathematical definition of the slope is very similar to the one we use every day. In mathematics, the slope is the relationship between the vertical and horizontal changes between two points on a surface or a line. In this sense, the slope can be found using the following expression:

$Average\hspace{3}rate\hspace{3}of\hspace{3}change=Slope=\frac{y_2-y_1}{x_2-x_1} =\frac{f(x_2)-f(x_1)}{x_2-x_1}$

So, the average rate of change of:

$f(x)=-x^2+3x+6$

Over the interval $-3$

Is:

$f(x_2)=f(3)=-(3)^2+3(3)+6=-9+9+6=6\\\\f(x_1)=f(-3)=-(-3)^2+3(-3)+6=-9-9+6=-12$

$\frac{\Delta y}{\Delta x} =\frac{f(x_2)-f(x_1)}{x_2-x_1} =\frac{6-(-12)}{3-(-3)} =\frac{18}{6}= 3$

Therefore, the average rate of change of this function over that interval is 3.

3 0

3 years ago