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UNO [17]
2 years ago
15

X^4+64 will be the perfect square by adding​

Mathematics
1 answer:
lions [1.4K]2 years ago
7 0

Answer:

(  { {x}^{2} })^{2} + 16 {x}^{2}   +  {8}^{2}  \\   ( {x}^{2}  + 8) ^{2}  \\ (  { {x}^{2} })^{2}  -  16 {x}^{2}   +  {8}^{2}  \\   ( {x}^{2}   - 8) ^{2}

<h3><em>+16x² or -16x² is the answer</em></h3>
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AB:BC is 3:4. Solve for x.
Sphinxa [80]
I got B but I'll show you how I got that answer.

Let's look at AB and BC. AB = 3 and BC = 4.
3/4 = 0.75

On the triangle, AB = 90. And BC = 10x - 20. We need to solve for x and prove that AB/BC = 0.75.

Let's start with Choice A.

10(11) - 20 = 90.

AB = 90
BC = 90.

90/90 = 1. It doesn't equal 0.75. Meaning this answer is wrong.

Now let's look at Choice B.

10(14) - 20 = 120.

AB = 90
BC = 120

90/120 = 0.75

So, 3:4 = 90:120 making Choice B the correct Answer. Let me know if this is correct
6 0
3 years ago
The number of chocolate chips in a bag of chocolate chip cookies is approximately normally distributed with mean of 1262 and a s
Andrew [12]

Answer:

a) 1186

b) Between 1031 and 1493.

c) 160

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with mean of 1262 and a standard deviation of 118.

This means that \mu = 1262, \sigma = 118

a) Determine the 26th percentile for the number of chocolate chips in a bag. ​

This is X when Z has a p-value of 0.26, so X when Z = -0.643.

Z = \frac{X - \mu}{\sigma}

-0.643 = \frac{X - 1262}{118}

X - 1262 = -0.643*118

X = 1186

(b) Determine the number of chocolate chips in a bag that make up the middle 95% of bags.

Between the 50 - (95/2) = 2.5th percentile and the 50 + (95/2) = 97.5th percentile.

2.5th percentile:

X when Z has a p-value of 0.025, so X when Z = -1.96.

Z = \frac{X - \mu}{\sigma}

-1.96 = \frac{X - 1262}{118}

X - 1262 = -1.96*118

X = 1031

97.5th percentile:

X when Z has a p-value of 0.975, so X when Z = 1.96.

Z = \frac{X - \mu}{\sigma}

1.96 = \frac{X - 1262}{118}

X - 1262 = 1.96*118

X = 1493

Between 1031 and 1493.

​(c) What is the interquartile range of the number of chocolate chips in a bag of chocolate chip​ cookies?

Difference between the 75th percentile and the 25th percentile.

25th percentile:

X when Z has a p-value of 0.25, so X when Z = -0.675.

Z = \frac{X - \mu}{\sigma}

-0.675 = \frac{X - 1262}{118}

X - 1262 = -0.675*118

X = 1182

75th percentile:

X when Z has a p-value of 0.75, so X when Z = 0.675.

Z = \frac{X - \mu}{\sigma}

0.675 = \frac{X - 1262}{118}

X - 1262 = 0.675*118

X = 1342

IQR:

1342 - 1182 = 160

7 0
3 years ago
The dot on the number line represents which fraction?
Ad libitum [116K]

0 \times 8 = 0(2 \times 8 = 16)
4 0
3 years ago
CORRECT ANSWER GETS BRAINLIEST
borishaifa [10]
6 (-9)-3/2=14
-108/2-3/2=14
-111/2 = 14
false

12+2=14
14=14

B
7 0
3 years ago
G(x) = -2x^3 - 12x^2 + 30x + 200
mafiozo [28]

Answer:

you have a cubic function right? what are you trying to do?? find intercepts?? need a little more information

8 0
3 years ago
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