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UNO [17]
2 years ago
15

X^4+64 will be the perfect square by adding​

Mathematics
1 answer:
lions [1.4K]2 years ago
7 0

Answer:

(  { {x}^{2} })^{2} + 16 {x}^{2}   +  {8}^{2}  \\   ( {x}^{2}  + 8) ^{2}  \\ (  { {x}^{2} })^{2}  -  16 {x}^{2}   +  {8}^{2}  \\   ( {x}^{2}   - 8) ^{2}

<h3><em>+16x² or -16x² is the answer</em></h3>
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Help please!!!
a_sh-v [17]

Answer:

yes thats good

Step-by-step explanation:

4 0
3 years ago
1. If a scale factor is applied to a figure and all dimensions are changed proportionally, what is the effect on the perimeter o
tester [92]

Answer:

Part 1) The perimeter of the new figure must be equal to the perimeter of the original figure multiplied by the scale factor (see the explanation)

Part 2) The area of the new figure must be equal to the area of the original figure multiplied by the scale factor squared

Part 3) The new figure and the original figure are not similar figures (see the explanation)

Step-by-step explanation:

Part 1) If a scale factor is applied to a figure and all dimensions are changed proportionally, what is the effect on the perimeter of the figure?

we know that

If all dimensions are changed proportionally, then the new figure and the original figure are similar

When two figures are similar, the ratio of its perimeters is equal to the scale factor

so

The perimeter of the new figure must be equal to the perimeter of the original figure multiplied by the scale factor

Part 2) If a scale factor is applied to a figure and all dimensions are changed proportionally, what is the effect on the area of the figure?

we know that

If all dimensions are changed proportionally, then the new figure and the original figure are similar

When two figures are similar, the ratio of its areas is equal to the scale factor squared

so

The area of the new figure must be equal to the area of the original figure multiplied by the scale factor squared

Part 3) What would happen to the perimeter and area of a figure if the dimensions were changed NON-proportionally? For example, if the length of a rectangle was tripled, but the  width did not change? Or if the length was tripled and the width was decreased by a factor of 1/4?​

we know that

If the dimensions were changed NON-proportionally, then the ratio of the corresponding sides of the new figure and the original figure are not proportional

That means

The new figure and the original figure are not similar figures

therefore

Corresponding sides are not proportional and corresponding angles are not congruent

so

<u><em>A) If the length of a rectangle was tripled, but the  width did not change?</em></u>

Perimeter

The original perimeter is P=2L+2W

The new perimeter would be P=2(3L)+2W ----> P=6L+2W

The perimeter of the new figure is greater than the perimeter of the original figure but are not proportionals

Area

The original area is A=LW

The new area  would be A=(3L)(W) ----> A=3LW

The area of the new figure is three times the area of the original figure but its ratio is not equal to the scale factor squared, because there is no single scale factor

<u><em>B) If the length was tripled and the width was decreased by a factor of 1/4?</em></u>

Perimeter

The original perimeter is P=2L+2W

The new perimeter would be P=2(3L)+2(W/4) ----> P=6L+W/2

The perimeter of the new figure and the perimeter of the original figure are not proportionals

Area

The original area is A=LW

The new area  would be A=(3L)(W/4) ----> A=(3/4)LW

The area of the new figure is three-fourth times the area of the original figure but its ratio is not equal to the scale factor squared, because there is no single scale factor

5 0
2 years ago
Alyssa saw 48 birds in a tree. How many dozen birds did Alyssa see?
Kamila [148]
4 dozen, he’s right ^
8 0
3 years ago
Two perpendicular lines intersect at the origin. If the slope of the first line is .5, what is the equation of the second line?.
Sedaia [141]
The origin is at the point (0,0). Therefore, the y-intercept will be 0. For two points to be perpendicular, the slopes must be opposite reciprocals of each other. .5 can be seen as 1/2, so the reciprocal is 2, and it is positive, making that 2 negative. Your equation would be y = -2x. 
3 0
3 years ago
What is the longest flagpole that could be shipped in a box that measures: 1 ft by 2 ft by 12 ft?
klemol [59]
A^2+b^2=C^2
=
4+144=148
The square root of 148 is 12.165
round it down to 12

Hope this helps
4 0
3 years ago
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