Answer:
Step-by-step explanation:
Here we have KP = PE (tangents from outside the circle)
Therefore, 2KP = PE + 1 = KP + 1
Hence, 2KP - KP = 1 or KP = 1 = PE
Since KE is the base of triangle KPE, where ∡ KPE = 60, and KP = PE, we have an isosceles triangle such that ∡PKE = ∡PEK
Hence, in ΔKPE, ∡KPE + ∡PKE + ∡PEK = 180
Therefore, 60° + ∡PKE + ∡PEK = 180
Hence, ∡PKE + ∡PEK = 180° - 60° = 120°
Because ∡PKE = ∡PEK, (base angles of isosceles triangle), we have;
∡PKE + ∡PEK = 2·∡PEK = 120° which gives
∡PEK = 60° = ∡PKE
Therefore, ∡KPE = ∡PEK = ∡PKE = 60°
Hence, ΔKPE is an equilateral triangle and KP = PE = EK = 1
EK = 1.
Answer:
x=6
Step-by-step explanation:
You can use trig for this
Cos (45)=
x=
x=6
Given: F = {(0, 1), (2, 4), (4, 6), (6, 8)} and G = {(2, 5), (4, 7), (5, 8), (6, 9), (7, 5)} (F - G) (6) =
Maslowich
<span>F = {(0, 1), (2, 4), (4, 6), (6, 8)}
G = {(2, 5), (4, 7), (5, 8), (6, 9), (7, 5)}
F(6) = 8
G(6) = 9
so
</span><span>(F - G) (6) = 8 - 9 = -1
</span>