james went out for a long walk . He walked 3 2/5 of the mile. then he sat down to take rest . After that he walked 5/7 of a mile
1 answer:
Answer:
Altogether James walked miles.
Step-by-step explanation:
The question involves mixed fractions. Mixed fractions are first converted into proper fractions and then any operation can be performed on them.
Given
Distance of first walk = of a mile
Distance of second walk = 5/7
In order to find how much he walked altogether, we have to find the sum of both fractions.
Hence,
Altogether James walked miles.
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<u>Answer:</u>
Sale tax paid by Katrina is 0.44 units of currency and total amount paid is 5.94 unit of currency.
<u> Solution:</u>
Given that Katrina goes to road runner after school and purchase following three products
A soda for 1.50
Chips for 3.50
Candy for 0.50
Also she pays 8% sales tax.
Need to determine amount paid in sales tax and total amount paid by Katrina.
lets first calculate amount she paid without taxes.
Total paid amount without taxes = 1.50 + 3.50 + 0.50 = 5.50
As she paid 8% sale tax , that is 8 % of 5.50
so sale tax paid =
<em>Total amount paid = Total amount paid without taxes + tax paid </em>
= 5.50 + 0.44 = 5.94
Hence sale tax paid by Katrina is 0.44 units of currency and total amount paid is 5.94 unit of currency.
The inequality is used to solve how many hours of television Julia can still watch this week is
The remaining hours of TV Julia can watch this week can be expressed is 3.5 hours
<h3><u>Solution:</u></h3>Given that Julia is allowed to watch no more than 5 hours of television a week
So far this week, she has watched 1.5 hours
To find: number of hours Julia can still watch this week
<em>Let "x" be the number of hours Julia can still watch television this week</em>
"no more than 5" means less than or equal to 5 ( ≤ 5 )
Juila has already watched 1.5 hours. So we can add 1.5 hours and number of hours Julia can still watch television this week which is less than or equal to 5 hours
number of hours Julia can still watch television this week + already watched ≤ Total hours Juila can watch
Thus the above inequality is used to solve how many hours of television Julia can still watch this week.
Solving the inequality,
Thus Julia still can watch Television for 3.5 hours