A square pyramid is shown. 4 m 6 m 6 m What is the surface area of the pyramid?

Mathematics

1 answer:

gladu [14]3 years ago

3 0

The answer is 18....

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If ΔABC ≌ ΔRPQ , ∠A = 35˚, ∠C=75˚ , Find the measure of ∠Q. *

Norma-Jean [14]

<h3>Answer: angle Q = 75 degrees</h3>

Explanation:

The order of ABC and RPQ is important so we can match up the angles like so

angle A = angle R .... first letters
angle B = angle P .... second letters
angle C = angle Q ... third letters

Meaning that angle Q = 75 since angle C is this measure.

3 0

3 years ago

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7- H ,0 am An average persons heart beats about 103,680 times a day and solve an equation to ﬁnd about how many times me average

Mrac [35]

103680÷24=4320
4320÷60=72
=72times/minute

8 0

3 years ago

What is the sum of X2-3x+7 and 3x2+5X-9

Pie

$x^2-3x+7+3x^2+5x-9=\ \ \ \ | combine\ like\ terms\\\\
4x^2+2x-2\\\\
Solution\ is\ 4x^2+2x-2.$

6 0

3 years ago

I really need help with this one please

natka813 [3]

The distance from the sun is option 2 5.59 astronomical units.

Step-by-step explanation:

Step 1; To solve the question we need two variables. P which represents the number of years a planet takes to complete a revolution around the Sun. This is given as 13.2 years in the question so P = 13.2 years. The other variable is the distance between the planet and the sun in astronomical units. We need to determine the value of this using the given equation.

Step 2; So we have to calculate the value of 'a' in Kepler's equation. But the exponential power $\frac{3}{2}$ is on the variable we need to find so we multiply both the sides by an exponential power of $\frac{2}{3}$ to be able to calculate 'a'.

P = $a^{\frac{3}{2} }$ , $P^{\frac{2}{3} }$ = $a^{\frac{3}{2}*\frac{2}{3} }$ , $P^{\frac{2}{3} }$ = a, $13.2^{\frac{2}{3} }$ = a = 5.58533 astronomical units.