First
224-108=116miles left
And 4 days left
116/4
=29 miles each day
Four to the fifth power is...
4•4•4•4•4=1,024
The area of a kite is (1/2) * x * y, where x and y are the length of the two diagonals. In this case, the length of the two diagonals are 10 ft and 2 ft.
<span>Plug that in the equation, we get 1/2 * 2 * 10. We multiply the 2 and 10 first to get 20, that leaves us with 1/2 x 20, which is 10, so the area of this kite is 10 ft squared.</span>
Answer: 10
Step-by-step explanation:
Since integral from 1 to 4 of f(x) =10
To evaluate integral from 2 to 8 of 2 times f(2x), using substitution method
Let U = 2x, dU = 2dx, dx = dU/2
Evaluate the limit, upper limit gives dU = 2*4 = 8, lower limit gives dU = 2*1 = 2.
Since this limit are the same as the limit for the question,
Therefore, F(4) - F(1) = F(8) - F(2) = 10
Substituting dx=dU/2
Gives,
Integral from 2 to 8 of 2 times f(2x)= (1/2)(2)(F(8)-F(2)) = 10
11/12
simplificado
de nada
