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koban [17]
3 years ago
6

Ashley earns money at a constant rate. Ashley earns $15 in 2.5 hours. We want to know how much money, m, Ashely will earn after

t hours. Write the linear equation in two variables that represent the amount of money she earned in any given time interval.
pls don't answer if you don't know so ppl don't spend their answers on that if they don't have plus
Mathematics
1 answer:
bogdanovich [222]3 years ago
6 0

Answer:

Step-by-step explanation:

$15/2.5hr=$6 so if earnings are y and hours worked is x then

y=6x

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Use long division to find a repeated decimal equivalency for the fraction 6/9
Sliva [168]

It gets repetitive really fast. The second verse is the same as the first. The result is ...

\dfrac{6}{9}=0.\overline{6}

4 0
3 years ago
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In ΔSTU, u = 900 cm, ∠T=49° and ∠U=14°. Find the length of s, to the nearest centimeter.
Artemon [7]

Answer:

3315

Step-by-step explanation:

delta math

8 0
3 years ago
Can you please do 1 to 10
ehidna [41]
1) 4(x-6)<2
2) 7n+19<8
3) 3(11+x)>=15
4) 4n-12<6
5) 2n+14>=1
6) 2(x+7)>=10
7) 11n-3>9
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10) 4(x+2)<14
3 0
4 years ago
I’ve been stuck can someone help
never [62]

Answer:

(a). A_{x} = \left[\begin{array}{cc}12&-4\\66&6\end{array}\right]

Step-by-step explanation:

\left \{ {{5x-4y=12} \atop {3x+6y=66}} \right.

A = \left[\begin{array}{cc}5&-4\\3&6\end{array}\right]

A_{x} = \left[\begin{array}{cc}12&-4\\66&6\end{array}\right]

A_{y} = \left[\begin{array}{cc}5&12\\3&66\end{array}\right]

5 0
3 years ago
21 7/8 - 8 5/12<br><br><br> Help
Vlada [557]
21 and 7/8-8 and 5/12
remember that 21 and 7/8=21+7/8 and 8 and 5/12=8+5/12 so

21+7/8-(8+5/12)
21+7/8-8-5/12
21-8+7/8-5/12
13+7/8-5/12

so 7/8 and 5/12
make bottom number the same
multiply 7/8 by 12/12 and multiply 5/12 by 8/8
7/8-5/12=84/96-40/96=(84-40)/96=44/96=11/24
so the answer is
13 and 11/24
7 0
3 years ago
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