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Margaret [11]
3 years ago
13

Which equation can be used to solve for x, the increase in side length of the square in inches?

Mathematics
2 answers:
lesya692 [45]3 years ago
6 0

Answer:

C) x2 + 8x – 65 = 0

Step-by-step explanation:

edge

Mekhanik [1.2K]3 years ago
5 0

Answer:

<em>x2 + 8x – 65 = 0</em>

Step-by-step explanation:

Complete question

<em>A square picture with a side length of 4 inches needs to be enlarged. The final area needs to be 81 square inches. Which equation can be used to solve for x, the increase in side length of the square in inches? x2 + 4x – 81 = 0 x2 + 4x – 65 = 0 x2 + 8x – 65 = 0 x2 + 8x – 81 = 0</em>

Given the initial side length = 4in

Initial area = L²

L is side length of the square

Initial area = 4²

Initial area = 16 square inches

Area of the enlarged square = 81 square inches

To get the constant term of the expression, we will find the difference in the areas

Difference = 85 - 16

Difference = 65 square units

The coefficient of x will be the 2 *initial area of the square

Given the standard form of an expression as

ax^2 + bx + c

a = 1, b = 2*4 = 8, c = -65

Substitute

x^2 + 8x - 65

This gives the required expression

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Answer:

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Step-by-step explanation:

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Solve the following linear quadratic system of equations algebraically.<br><br> y=^2+3x-2<br> y+3=5x
USPshnik [31]

Answer:

x=1

y=2

Step-by-step explanation:

y=x^2+3x-2 , y+3=5x

Replace all occurrences of y in y+3=5x with x^2+3x-2.

(x^2+3x-2)+3=5x

y=x^2+3x-2

Add -2 and 3.

x^2+3x+1=5x

y=x^2+3x-2

Subtract 5x from both sides of the <u>equation.</u>

x^2+3x+1-5x=0

y=x^2+3x-2

Subtract 5x from 3x.

x^2-2x+1=0

y=x^2+3x-2

Rewrite 1 as 1^2.

x^2-2x+1^2=0

y=x^2+3x-2

Check that the middle <u>term</u> is two times the <u>product</u> of the numbers being squared in the first <u>term</u> and third <u>term</u>.

2x=2 · x · 1

y=x^2+3x-2

Rewrite the <u>polynomial</u>.

x^2-2 · x · 1 + 1^2=0

y=x^2+3x-2

Factor using the <u>perfect square</u>

<u>trinomial</u> rule a^2-2ab+b^2=(a-b)^2,

where a = x and b = 1.

(x-1)^2=0

y=x^2+3x-2

<u>Set</u> the x-1 equal to 0.

x-1=0

y=x^2+3x-2

Add 1 to both sides of the <u>equation</u>.

x=1

y=x^2+3x-2

Replace all occurrences of x in

y=x^2+3x-2 with 1.

y=(1)^2+3(1)-2

x=1

y=2

3 0
3 years ago
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