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raketka [301]
3 years ago
15

What is the practical application of the information acquired by science.

Computers and Technology
1 answer:
mrs_skeptik [129]3 years ago
5 0

Answer:

Technology

Explanation:

The correct answer is - Technology

Reason -

Technology is the sum of techniques, skills, methods, and processes that are used in the production of goods or services or in the accomplishment of objectives, such as scientific investigation.

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Explanation:

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For a loop counter, the appropriate data type would be:
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Answer:a) int

Explanation: Loop counter is the kind of program that has the major function of counting the start value to the destination value in the form of integer.The integer is used for counting the values in a particular loop is known as the loop control variable.Therefore the accurate datatype for the loop counter to count the values should be of int type.

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Read 2 more answers
Selection Sort List the resulting array after each iteration of the outer loop of the selection sort algorithm. Indicate the num
Lady bird [3.3K]

Solution :

Initial array = $\text{C,Q,S,A,X,B,T}$

$n= 7$(length of the array)

$\text{1st}$ Iteration:

i = 1

  j = 1

  $\text{a[j-1]}$ = C

  a[j] = Q

  since $\text{a[j-1]}$ < a[j] , break from inner loop

 

Number of comparisons in 1st Iteration = 1

After 1st Iteration:

Array : C,Q,S,A,X,B,T

2nd Iteration:

i = 2

  j = 2

  a[j-1] = Q

  a[j] = S

  since a[j-1] < a[j], break from inner loop

 

Number of comparisons in 2nd Iteration = 1

After 2nd Iteration:

Array : C,Q,S,A,X,B,T

3rd Iteration:

i = 3

  j = 3

  a[j-1] = S

  a[j] = A

  since a[j-1] > a[j], exchange a[2] with a[3]

  Array : C,Q,A,S,X,B,T

 

  j = 2

  a[j-1] = Q

  a[j] = A

  since a[j-1] > a[j], exchange a[1] with a[2]

  Array : C,A,Q,S,X,B,T

 

  j = 1

  a[j-1] = C

  a[j] = A

  since a[j-1] > a[j], exchange a[0] with a[1]

  Array : A,C,Q,S,X,B,T

 

  j = 0, break from inner loop

Number of comparisons in 3rd Iteration = 3

After 3rd Iteration:

Array : A,C,Q,S,X,B,T

4th Iteration:

i = 4

  j = 4

  a[j-1] = S

  a[j] = X

  since a[j-1] < a[j], break from inner loop

 

Number of comparisons in 4th Iteration = 1

After 4th Iteration:

Array : A,C,Q,S,X,B,T

5th Iteration:

i = 5

  j = 5

  a[j-1] = X

  a[j] = B

  since a[j-1] > a[j], exchange a[4] with a[5]

  Array : A,C,Q,S,B,X,T

 

  j = 4

  a[j-1] = S

  a[j] = B

  since a[j-1] > a[j], exchange a[3] with a[4]

  Array : A,C,Q,B,S,X,T

 

  j = 3

  a[j-1] = Q

  a[j] = B

  since a[j-1] > a[j], exchange a[2] with a[3]

  Array : A,C,B,Q,S,X,T

 

  j = 2

  a[j-1] = C

  a[j] = B

  since a[j-1] > a[j], exchange a[1] with a[2]

  Array : A,B,C,Q,S,X,T

 

  j = 1

  a[j-1] = A

  a[j] = B

  since a[j-1] < a[j], break from inner loop

 

Number of comparisons in 5th Iteration = 5

After 5th Iteration:

Array : A,B,C,Q,S,X,T

6th Iteration:

i = 6

  j = 6

  a[j-1] = X

  a[j] = T

  since a[j-1] > a[j], exchange a[5] with a[6]

  Array : A,B,C,Q,S,T,X

 

  j = 5

  a[j-1] = S

  a[j] = T

  since a[j-1] < a[j], break from inner loop

 

Number of comparisons in 6th Iteration = 2

After 6th Iteration:

Array : A,B,C,Q,S,T,X

Sorted Array : A B C Q S T X  

4 0
3 years ago
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