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raketka [301]
3 years ago
15

What is the practical application of the information acquired by science.

Computers and Technology
1 answer:
mrs_skeptik [129]3 years ago
5 0

Answer:

Technology

Explanation:

The correct answer is - Technology

Reason -

Technology is the sum of techniques, skills, methods, and processes that are used in the production of goods or services or in the accomplishment of objectives, such as scientific investigation.

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It converts Assembly Language into machine language?​
docker41 [41]

Answer:

An assembler.

Explanation:

Input is (as with any programming language) files with lists of instructions (typically assembler mnemonics), output is a binary format representing these instructions in machine language.

6 0
3 years ago
I need help with this plz! It’s for a test and I really need help
Bas_tet [7]

Answer:

c

Explanation:

assuming you are coding in python and have not install any calculation codes, the answer is most likely c

4 0
3 years ago
What level of system and network configuration is required for cui?
andrey2020 [161]

The level of system and network configuration is required for Cui will be "Moderate confidentiality".

  • The data that really should be safeguarded or disseminated under appropriate regulations, rules, and conservative government objectives or guidelines, would be considered as CUI.
  • The FISMA demands CUI Fundamental to somehow be safeguarded somewhere at the FISMA Conservative category and may even be labeled as CUI as well as regulated.

Thus the above answer is right.

Learn more:

brainly.com/question/14083709

4 0
2 years ago
Which wireless standard has bandwidth up to 54 Mbps and signals in a regulated frequency spectrum around 5 GHz?
Tamiku [17]

Answer:

802.11a

Explanation:

802.11a supports bandwidth of 54 Mbps in a regulated frequency spectrum of 5 GHz. 802.11a also referred to as Wi-fi 2. 802.11a is basically costs higher than 802.11b though both were created at the same time. Hence 802.11b is more popular than 802.11a . All of them are developed by IEEE.

4 0
3 years ago
Write a C++ program that reads from the standard input and counts the number of times each word is seen. A word is a number of n
Rufina [12.5K]

Answer:

#include <stdio.h>

#include <string.h>

#include <ctype.h>

 

struct detail

{

   char word[20];

   int freq;

};

 

int update(struct detail [], const char [], int);

 

int main()

{

   struct detail s[10];

   char string[100], unit[20], c;

   int i = 0, freq = 0, j = 0, count = 0, num = 0;

 

   for (i = 0; i < 10; i++)

   {

      s[i].freq = 0;

   }

   printf("Enter string: ");

   i = 0;

   do

   {

       fflush(stdin);

       c = getchar();

       string[i++] = c;

 

   } while (c != '\n');

   string[i - 1] = '\0';

   printf("The string entered is: %s\n", string);

   for (i = 0; i < strlen(string); i++)

   {

       while (i < strlen(string) && string[i] != ' ' && isalnum(string[i]))

       {

           unit[j++] = string[i++];

       }

       if (j != 0)

       {

           unit[j] = '\0';

           count = update(s, unit, count);

           j = 0;

       }

   }

 

   printf("*****************\nWord\tFrequency\n*****************\n");

   for (i = 0; i < count; i++)

   {

       printf("%s\t   %d\n", s[i].word, s[i].freq);

       if (s[i].freq > 1)

       {

           num++;

       }

   }

   printf("The number of repeated words are %d.\n", num);

 

   return 0;

}

 

int update(struct detail s[], const char unit[], int count)

{

   int i;

 

   for (i = 0; i < count; i++)

   {

       if (strcmp(s[i].word, unit) == 0)

       {

           s[i].freq++;

 

           return count;

       }

   }

   /*If control reaches here, it means no match found in struct*/

   strcpy(s[count].word, unit);

   s[count].freq++;

 

   /*count represents the number of fields updated in array s*/

   return (count + 1);

}

4 0
3 years ago
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