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serg [7]
2 years ago
7

The distance from the pitcher’s mound to home plate is 60.5 feet. Does this form a right triangle with first base? Explain your

reasoning

Mathematics
1 answer:
goldenfox [79]2 years ago
6 0

Answer:

NO.

Step-by-step explanation:

60.5 + 60.5 = 121

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Create a model of your choice to represent the
stealth61 [152]

Hey there!

“6 + r = 8”

• FIRST: FIRST THE EQUATION

r + 6 = 8

• SECOND: SUBTRACT by 6 on BOTH SIDES

r + 6 – 6 = 8 – 6

CANCEL out; 6 – 6 because that gives you 0

KEEP: 8 – 6 because that helps solve for your r-value

• THIRD: SOLVE FOR YOUR EQUATION

8 – 6 = r

• FOURTH: ANSWER THE QUESTION

8 – 6 = 2

FIFTH: ANSWER

r = 2 ☑️

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)

7 0
3 years ago
7(x+4)−6(x+3)=x+5 what is x
shusha [124]

Answer: No solution

Step-by-step explanation:

7(x+4) - 6(x+3) = x + 5

7x + 28 - 6x - 18 = x + 5     distributing

7x - 6x - x = -28 + 18 +5

0 = -5       <u>Not true</u>

No solution

7 0
3 years ago
Read 2 more answers
A line passes through (-6, 10) and (4, -10). What is the slope?
FromTheMoon [43]
M= -2 , hope this help you <3
6 0
3 years ago
Need help with this question
andreyandreev [35.5K]
You multiply the numbers and add the variable's exponents.

7 0
3 years ago
What is the perimeter of the triangle shown on the coordinate plane,to the nearest tenth of a unit ?
ollegr [7]

Answer:

25.6 units

Step-by-step explanation:

From the figure we can infer that our triangle has vertices A = (-5, 4), B = (1, 4), and C = (3, -4).

First thing we are doing is find the lengths of AB, BC, and AC using the distance formula:

d=\sqrt{(x_2-x_1)^{2} +(y_2-y_1)^{2}}

where

(x_1,y_1) are the coordinates of the first point

(x_2,y_2) are the coordinates of the second point

- For AB:

d=\sqrt{[1-(-5)]^{2}+(4-4)^2}

d=\sqrt{(1+5)^{2}+(0)^2}

d=\sqrt{(6)^{2}}

d=6

- For BC:

d=\sqrt{(3-1)^{2} +(-4-4)^{2}}

d=\sqrt{(2)^{2} +(-8)^{2}}

d=\sqrt{4+64}

d=\sqrt{68}

d=8.24

- For AC:

d=\sqrt{[3-(-5)]^{2} +(-4-4)^{2}}

d=\sqrt{(3+5)^{2} +(-8)^{2}}

d=\sqrt{(8)^{2} +64}

d=\sqrt{64+64}

d=\sqrt{128}

d=11.31

Next, now that we have our lengths, we can add them to find the perimeter of our triangle:

p=AB+BC+AC

p=6+8.24+11.31

p=25.55

p=25.6

We can conclude that the perimeter of the triangle shown in the figure is 25.6 units.

6 0
3 years ago
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