What is the sum of 4.2x10^5 and 5.3x10^5

1 answer:

4 0

The answer is: " 9.5 * 10⁵ " .
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4.2 * 10⁵ + 5.3 * 10⁵ = (4.2 + 5.3) * 10⁵ = 9.5 * 10⁵ .
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HELP NEEDED!!!! MUCH APPRECIATED

jeka94

We have

$t_1 + t+2 = \dfrac{\sqrt{s}}{4} + \dfrac{s}{1100} = .5$

Multiplying through by 1100,

$275 \sqrt{s} + s = 550$

$275 \sqrt{s} = 550 - s$

Squaring (which means we need to check later),

$275^2 s = (550 - s)^2 = 550^2 - 1100 s + s^2$

$0 = s^2 - (1100 + 275^2) s + 550^2$

$0 = s^2 - 76725 s + 302500$

$s = \frac 1 2 (76725 \pm 1375 \sqrt{3113} )$

$s \approx 3.94285 \textrm{ or } s \approx 76721.0571$

Clearly there's no way that giant number would work; must be extraneous.

Answer: 3.94

Merry Christmas!

7 0

3 years ago

a country's population in 1990 was 134 million. in 2000 it was a 139 million. estimate the population in 2014 using the exponent

yuradex [85]

F=ir^t

139=134r^10

139/134=r^10

r=(139/134)^(1/10) then:

f=134(139/134)^(t/10) so in 2014, t=24 so

f=134(139/134)^(2.4)

f≈146 million (to nearest million)

Some will say that you have to use the exponential function, but it really gives you the same answer...even for continuous compounding :)...

A=Pe^(kt)

139=134e^(10k)

139/134=e^(10k)

ln(139/134)=10k

k=ln(139/134)/10 so

A=134e^(t*ln(139/134)/10) when t=24

A=134e^(2.4*ln(139/134))

A≈146 million (to nearest million)

The only real reason or advantage to using A=Pe^(kt) is when you start getting into differential equations...

6 0

3 years ago

if P(x)=1+6x-5x^2 represents the profit in selling x thousand Boombotix speakers, how many speakers should be sold to maximize p

Rashid [163]

Answer:

600

Step-by-step explanation:

$p(x) = 1 + 6x - 5x^2$