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Eva8 [605]
3 years ago
15

Solve the following quadratic equation:x/x+3 = 5/2x+6​

Mathematics
1 answer:
Leni [432]3 years ago
7 0

Answer:

x=5/2, x=-3\\

Step-by-step explanation:

x(2x+6)=5(x+3)\\2x^2+6x=5x+15\\2x^2+6x-5x-15=0\\2x^2+x-15=0\\2x^2+6x-5x-15=0\\2x(x+3)-5(x+3)=0\\(2x-5)(x+3)=0\\2x-5=0, x+3=0\\x=5/2, x=-3\\

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Can you help me answer the question please :l
liberstina [14]

27

You can find the area of a triangle with base b and height h using this formula.

A=

1

2

bh

The triangle has base b=6miles and height h=9miles.

Find the area.

A

=  

1

2

bh

=  

1

2

(6)(9)

= (3)(9)

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4 0
3 years ago
Last week, Ray worked 46 hours. He incorrectly calculated he earned $45 of additional pay. What was Ray's error when he miscalcu
astra-53 [7]

Answer: +$45

Step-by-step explanation: if his actual pay for the week was $100 then from the question he incorrectly calculated it as {$100 + $45} = $145 which is $45 above his actual pay.

Error = measured value - actual

value.

= $145 -$100 =$45.

NOTE: since the value he assumed{$145} is greater than his actual pay{$100}, we have to include a positive sign to the error{$45}.

Therefore, Error = +$45.

6 0
3 years ago
Can somebody answer this please.
marishachu [46]
The answer to the question is True
3 0
3 years ago
Sea un cuadrado de 2 pulgadas de lado uniendo los puntos medios se obtiene otro cuadrado inscrito en el anterior si repetimos es
Ne4ueva [31]

Answer:

1) La serie geométrica formada es

4, 2, 1,..., ∞

2) La suma al infinito de las áreas de los cuadrados es 8 in.²

Step-by-step explanation:

1) El área del primer cuadrado, a₁ = 2² = 4 pulgadas²

El área del siguiente cuadrado, a₂ = (√ (1² + 1²)) ² = (√2) ² = 2 pulg²

El área del siguiente cuadrado, a₃ = ((√ (2) / 2) ² + (√ (2) / 2) ²) = 1 pulg²

Por lo tanto, la razón común, r = a₂ / a₁ = 2/4 = a₃ / a₂ = 1/2

Las áreas de los cuadrados progresivos forman una progresión geométrica como sigue;

4, 4×(1/2), 4 ×(1/2)²,...,4×(1/2)^{\infty}

De donde obtenemos la serie geométrica formada de la siguiente manera;

4, 2, 1,..., ∞

2) La suma de 'n' términos de una progresión geométrica hasta el infinito para -1 <r <1 se da como sigue;

S_{\infty} = \dfrac{a}{1 - r}

Por lo tanto, la suma de las áreas de los cuadrados hasta el infinito se obtiene sustituyendo los valores de 'a' y 'r' en la ecuación anterior de la siguiente manera;

La \ suma \ al \ infinito \ del \ cuadrado \ S_{\infty}  = \dfrac{4 \ in.^2}{1 - \dfrac{1}{2} } = \dfrac{4 \ in.^2}{\left(\dfrac{1}{2} \right)} = 2 \times 4 \ in.^2= 8 \ in.^2

La suma al infinito de las áreas de los cuadrados, S_{\infty} = 8 in.²

7 0
3 years ago
Timothy purchased a computer for $1,000. The value of the computer depreciates by 20% every year.
Vesna [10]

1.exponential decay 2. 0.2 3. 80% 4. 3 years

8 0
3 years ago
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