This is the concept of algebra, let the width be x
height=x-4
length=2x+10
the volume of the box is:
volume=length*width*height
=x(x-4)(2x+10)
expanding the above we get:
(x^2-4x)(2x+10)
=x^2(2x+10)-4x(2x+10)
=2x^3+2x^2-40x=264
solving the above we get real solution will be
x=6
thus we conclude that the width is x=6 inches
length=2*6+10=22 inches
height=x-4=6-4=2 inches
thus the dimension will be:
width=6 inches, length=22 inches, height=2 inches
I = 42t
When t = 5, I = 42*5 = 210
When t = 6, I = 42*6 = 252
When t = 7, I = 42*7 = 294
When t = 8, I = 42*8 = 336
When t = 9, I = 42*9 = 378
When t = 10, I = 42*10 = 420
Answer:
thats a hard one..
Step-by-step explanation:
I’m not too sure if I did it correct, but the answer I got was -6x^2+36. I just assumed you’d solve it as usual and then multiply (-3) after distributing-2 to x^2-6. Hope this helps.
Radius = sqrt(18) = 3*sqrt(2)
diameter = 2(3sqrt(2)) = 6sqrt(2)
