It is if my calculations are correct 1250 least thats what my calculator said..
Answer:
72000
Step-by-step explanation:
First five digit number is 10000
And the last five digit number is 99999.
There are 99999-10000+1 five digits in all.
That simplifies to 89999+1=90000.
Any number whose units digit is 5 or 0 is divisble by 5.
10000 is the first five digit number that is divisble by 5.
10000+5k where k is a positive integer can be used to find any after.
The last five digit number divisible by 5 is 99995. What is k then?
10000+5k=99995
5k=89995
k=89995/5
k=17999
How many 5 digit numbers are divisble by 5?
So the first one happens at k=0 and the last one happens at k=17999.
How many numbers is that? 17999+1=18000.
So the number of 5 digit numbers that aren't divisble by 5 is 90000-18000=72000
Answer: -x
Apply Multiplicative Distribution Law:- 1/5 * 5x - 1/5 * 20 - 1/2 * 4x - 1/2 *(-8)
Determine the sign for multiplication or division: 1/5 * 5x - 1/5 * 20 - 1/2 * 4x + 1/2 * 8
Cross out the common factor: x - 1/5 * 20 - 1/2 * 4x + 1/2 * 8
Cross out the common factor: x - 4 - 1/2 * 4x + 1/2 * 8 - 4 - 2x + 1/2 * 8
Cross out the common factor: x - 4 - 2x + 1/2 * 8
Cross out the common factor: x - 4 - 2x + 4
Reorder and gather like terms: (x - 2x) + (- 4 + 4)
Collect coefficients for the like terms: (1 - 2) * x + (- 4 + 4)
Calculate the sum or difference : - x + (- 4 + 4)
The sum of two opposites equals 0: -x
Answer: -x
Learn more about Multiplicative Distribution Law here:brainly.com/question/2898526
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