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STALIN [3.7K]
3 years ago
10

"45 meters north" is an example of

Physics
1 answer:
avanturin [10]3 years ago
5 0

Answer:

Displacement

Explanation:

The quantity 45m north is a typical example of displacement.

Displacement is the distance traveled by a body in a specific direction. Displacement is a vector quantity with both magnitude and direction.

  • When we are specifying the displacement of a body, the direction must be indicated accurately.
  • Therefore, the quantity given is displacement
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Technically, they do have a skeleton. The hard shell it has is called an exoskeleton. It works just like our skeleton, in terms of muscles and support. And, it protects from harm, similar to the way our skin protects the inside of our body from dirt and such.
5 0
4 years ago
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The initial speed of a body is 3.28 m/s. What is its speed after 2.32 s if it accelerates
Helga [31]
Final velocity = initial velocity + acceleration * time

v = u + at

v = 3.28 + 2.32 * 2.08

v = 3.28 + 4.83

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6 0
3 years ago
How does surface texture affect friction
Nadya [2.5K]

Answer:

The rougher a surface is, the more friction it can create.

Explanation:

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4 0
3 years ago
A skydiver of mass 87 kg falls straight down. If air resistance exerts 355 N of force on him as he falls, what is the net force
alukav5142 [94]

Answer:

497.6 N

Explanation:

From the question,

The net force on the skydiver = weight of the skydiver- the resistive force of air

F' = W-F...................... Equation 1

Where W = weight of the skydiver, F = resistive force of air.

But,

W = mg................ Equation 2

Where m = mass of the skydiver, g = acceleration due to gravity.

Substitute equation 2 into equation 1

F' = mg-F............ Equation 3

Given: m = 87 kg, F = 355 N, g = 9.8 m/s²

Substitute these values into equation 3

F' = 87(9.8)-355

F' = 852.6-355

F' = 487.6 N

6 0
3 years ago
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g If a car takes a banked curve at less than the ideal speed, friction is needed to keep it from sliding toward the inside of th
Reil [10]

Answer:

Speed; v = 17 m/s

Explanation:

We are given;

Radius; r = 110m

Angle; θ = 15°

Now, we know that in circular motion,

v² = rg•tanθ

Thus,

v = √(rg•tanθ)

Where,

v is velocity

r is radius

g is acceleration due to gravity

θ is the angle

Thus,

v = √(rg•tanθ) = √(110 x 9.8•tan15)

v = √(288.85)

v = 17 m/s

8 0
3 years ago
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