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Mamont248 [21]
3 years ago
9

-2x(6x^4 -7x^2 +x-5 in standard form pls

Mathematics
1 answer:
LuckyWell [14K]3 years ago
8 0

Answer:

-12x^5 + 14x^3 -2x^2 + 10x

Step-by-step explanation:

-2x(6x^4 -7x^2 +x-5) =

-12x^5 + 14x^3 -2x^2 + 10x

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y=-1/2x+2

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go one up and go to the left 2 times and connect the dots

6 0
2 years ago
I need help 3-6 pleasr
Colt1911 [192]
3) Mathematical expression would be:
 412 - 65 + 0.50x
Where, x = Number of Texts sent

4) Product means result after multiplication, sum after addition, quotient is the result of division with remainder, and difference is how far two numbers are in their magnitude.
"Per" tells us the magnitude for an Unit value.

5) Associative property = (a+b) + c = a+ (b+c)
Commutative property = a + b = b + a
Distributive Property = a(b+c) = ab+bc

They all have their unique characteristics and can be differentiated on that basis.

6) They all are same.
At the end, without parentheses and in proper symbol, it would be equal to -3/4

Hope this helps!
4 0
3 years ago
HELP! o.o
goblinko [34]
1/2 of getting an even number and 1/6 of getting a 5.
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3 years ago
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Math again yay!...Ew math
Sliva [168]

Answer:

The graph of g(x) is wider.

Step-by-step explanation:

Parent function:

f(x)=x^2

New function:

g(x)=\left(\dfrac{1}{2}x\right)^2=\dfrac{1}{4}x^2

<u>Transformations</u>:

For a > 0

f(x)+a \implies f(x) \: \textsf{translated}\:a\:\textsf{units up}

f(x)-a \implies f(x) \: \textsf{translated}\:a\:\textsf{units down}

\begin{aligned} y =a\:f(x) \implies & f(x) \: \textsf{stretched/compressed vertically by a factor of}\:a\\ & \textsf{If }a > 1 \textsf{ it is stretched by a factor of}\: a\\  & \textsf{If }0 < a < 1 \textsf{ it is compressed by a factor of}\: a\\\end{aligned}

\begin{aligned} y=f(ax) \implies & f(x) \: \textsf{stretched/compressed horizontally by a factor of} \: a\\& \textsf{If }a > 1 \textsf{ it is compressed by a factor of}\: a\\  & \textsf{If }0 < a < 1 \textsf{ it is stretched by a factor of}\: a\\\end{aligned}

If the parent function is <u>shifted ¹/₄ unit up</u>:

\implies g(x)=x^2+\dfrac{1}{4}

If the parent function is <u>shifted ¹/₄ unit down</u>:

\implies g(x)=x^2-\dfrac{1}{4}

If the parent function is <u>compressed vertically</u> by a factor of ¹/₄:

\implies g(x)=\dfrac{1}{4}x^2

If the parent function is <u>stretched horizontally</u> by a factor of ¹/₂:

\implies g(x)=\left(\dfrac{1}{2}x\right)^2

Therefore, a vertical compression and a horizontal stretch mean that the graph of g(x) is wider.

4 0
1 year ago
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