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Lerok [7]
3 years ago
9

Which of the following would occur if the Thrush population was to suddenly decrease?

Chemistry
2 answers:
Ulleksa [173]3 years ago
6 0
The answer is B because if the thrush were to decrease that would give eagles leas food to rely on
sineoko [7]3 years ago
6 0
Answer- B

Reasoning: Since Eagles directly eat Thrush, their populations would decrease.

The other answers are wrong because with the first choice, Eagles would not increase in population if one of their food sources were removed. For the third choice, Dragonflies wouldn’t increase. Since Thrush eat Dragonflies, the disappearance of Thrush wouldn’t hurt the population of Dragonflies. Lastly, The last option is wrong because corn isn’t reliant on animals to survive. If Thrush disappear, corn will not be affected. This leaves B. to be the answer.
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You are preparing some solutions for your instructor and have been asked to prepare 3.00 L of a 0.250M sodium hydroxide solution
grigory [225]

Answer:

C. 30.0 g NaOH and add water until the final solution has a volume of 3.00 L.

Explanation:

Molarity of a substance , is the number of moles present in a liter of solution .

M = n / V

M = molarity

V = volume of solution in liter ,

n = moles of solute ,

from the question ,

M =  0.250M

V  = 3.00 L

M = n / V

n = M * v

n = 0.250M * 3.00 L = 0.75 mol

Moles is denoted by given mass divided by the molecular mass ,

Hence ,

n = w / m

n = moles ,

w = given mass ,

m = molecular mass .

From the question ,

n = 0.75 mol NaOH

m = molecular mass of NaOH = 40 g/mol

n = w / m

w = n * m

w = 0.75 mol * 40 g/mol = 30.0 g

Hence , by using 30.0 g of NaOH and dissolving it to make up the volume to 3 L , a solution of 0.250 M can be prepared .

4 0
3 years ago
Express in scientific notation. Choose the answer with the proper number of significant figures.
bazaltina [42]

Answer:

4.5 times 10 = 45

Explanation:

"Non-zero digits are always significant. Any zeros between two significant digits are significant. A final zero or trailing zeros in the decimal portion ONLY are significant."

3 0
3 years ago
Balance <br> Al(OH)3 + H2SO4 → Al2(SO4)3 + H2O
Delicious77 [7]

Equation balance:

2Al(OH)3 + 3H2SO4 → Al2(SO4)3 + 6H2O

2Al(OH)3+3H2SO4

H=12

SO4=3

O=6

Al=2

Al2(SO4)3+6H2O

H=12

SO4=3

O=6

Al=2

8 0
3 years ago
Match the wave with its definition. (Lesson 4.03-4.03)
Lady_Fox [76]

The correct wave that matched its definition is:

  • Transverse Wave - A wave that has a disturbance that is perpendicular to the wave motion. The wave motion is moving side to side, the energy will be moving up and down.

  • Longitudinal Wave - The disturbance is parallel to the wave motion. In a longitudinal wave, the energy, and the motion

A wave is known to be a disturbance that travels through a medium and transfers energy from one point to another without causing any permanent displacement of the medium itself.

We have two forms of wave namely the transverse waves and the longitudinal waves.

When the vibration of a medium is perpendicular to the wave direction, the kind of wave formed is known as a transverse wave.

When the vibration of a medium is parallel to the wave direction, the kind of wave formed is known as a longitudinal wave.

Learn more here: brainly.com/question/15923236

6 0
3 years ago
A science teacher has a supply of 20% saline solution and a supply of 50% saline solution. How much of each solution should the
lilavasa [31]

Answer:

<h2>B)</h2>

Explanation:

\text{Let}\\\\x-\text{a volume of}\ 20\%\ \text{saline solution}\\\\y-\text{a volume of }\ 50\%\ \text{saline solution}\\\\p\%=\dfrac{p}{100}\\\\20\%=\dfrac{20}{100}=\dfrac{2}{10}=0.2\\\\50\%=\dfrac{50}{100}=\dfrac{5}{10}=0.5\\\\0.2x-\text{a volume of salt in }\ 20\%\ \text{saline solution}\\0.5y-\text{a volume of salt in }\ 50\%\ \text{saline solution}\\\\60mL-\text{a volume of}\ 28\%\ \text{saline solution}\\\\28\%=\dfrac{28}{100}=0.28

0.28\cdot60mL=16.8mL-\text{a volume of salt in }\ 28\%\ \text{saline solution}\\\\\text{Equations}\\\\(1)\qquad x+y=60\\(2)\qquad0.2x+0.5y=16.8

\left\{\begin{array}{ccc}x+y=60\\0.2x+0.5y=168&\text{multiply both sides by 10}\end{array}\right\\\left\{\begin{array}{ccc}x+y=60&\text{multiply both sides by (-2)}\\2x+5y=168}\end{array}\right\\\underline{+\left\{\begin{array}{ccc}-2x-2y=-120\\2x+5y=168}\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad3y=48\qquad\text{divide both sides by 3}\\.\qquad y=16

\text{Put the value of}\ y\ \text{to the first equation:}\\\\x+16=60\qquad\text{subtract 16 from both sides}\\x=44

6 0
4 years ago
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