1s^2 2s^2 2p^6 for the Mg2+ ion.
Answer:
The molarity of the dissolved NaCl is 6.93 M
Explanation:
Step 1: Data given
Mass of NaCl = 100.0 grams
Volume of water = 100.0 mL = 0.1 L
Remaining mass NaCl = 59.5 grams
Molar mass NaCl= 58.44 g/mol
Step 2: Calculate the dissolved mass of NaCl
100 - 59. 5 = 40.5 grams
Step 3: Calculate moles
Moles NaCl = 40.5 grams / 58.44 g/mol
Moles NaCl = 0.693 moles
Step 4: Calculate molarity
Molarity = moles / volume
Molarity dissolved NaCl = 0.693 moles / 0.1 L
Molarity dissolved NaCl = 6.93 M
The molarity of the dissolved NaCl is 6.93 M
Answer:
44,901 kilo Joule heat is released when
grams of ammonia is produced.
Explanation:
Moles of ammonia gas produced :

According to reaction, when 2 moles of ammonia are produced 9.18 kilo joules of energy is also released.
So, When 978.235 moles of ammonia gas is produced the energy released will be:

(negative sign indicates that energy is released as heat)
44,901 kilo Joule heat is released when
grams of ammonia is produced.
First find the mass
44.1 ml @ 1.55 g/mL = 68.355 grams of Ca
the equation
Ca + O2 → CaO
= 55 grams of O2