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liq [111]
3 years ago
7

Match the wave with its definition. (Lesson 4.03-4.03)

Chemistry
1 answer:
Lady_Fox [76]3 years ago
6 0

The correct wave that matched its definition is:

  • Transverse Wave - A wave that has a disturbance that is perpendicular to the wave motion. The wave motion is moving side to side, the energy will be moving up and down.

  • Longitudinal Wave - The disturbance is parallel to the wave motion. In a longitudinal wave, the energy, and the motion

A wave is known to be a disturbance that travels through a medium and transfers energy from one point to another without causing any permanent displacement of the medium itself.

We have two forms of wave namely the transverse waves and the longitudinal waves.

When the vibration of a medium is perpendicular to the wave direction, the kind of wave formed is known as a transverse wave.

When the vibration of a medium is parallel to the wave direction, the kind of wave formed is known as a longitudinal wave.

Learn more here: brainly.com/question/15923236

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How many milligrams of a 20mg sample of cesium-137 remain after 60 years
andrey2020 [161]
Cs -137 has a half life of about 30 years. If 60 years pass, there is two half lives passed so 1/2 * 1/2= 1/4. Take 1/4 and multiply it with the mass given:
(1/4)*20mg=5mg left
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I believe the answer is option B. The bonded pair of valence electrons are shown using circles
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Answer:

The reaction rates cannot charge

Explanation:

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The synthesization of new carbon compounds is studied in ____ chemistry?
oee [108]

Answer: Organic

Explanation:

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3 years ago
Enter your answer in the provided box. The usefulness of radiocarbon dating is limited to objects no older than 50,000 yr. What
guapka [62]

Answer : The percent of the carbon−14 left is, 0.242 %

Explanation :

This is a type of radioactive decay and all radioactive decays follow first order kinetics.

To calculate the rate constant, we use the formula :

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{5.73\times 10^3\text{ years}}

k=1.205\times 10^{-4}\text{ years}^{-1}

Now we have to calculate the amount left.

Expression for rate law for first order kinetics is given by :

k=\frac{2.303}{t}\log\frac{a}{a-x}

where,

k = rate constant  = 1.205\times 10^{-4}\text{ years}^{-1}

t = time taken for decay process  = 50000 years

a = initial amount or moles of the reactant  = 7 g

a - x = amount or moles left after decay process  = ?

Putting values in above equation, we get:

1.205\times 10^{-4}=\frac{2.303}{50000\text{ years}}\log\frac{7g}{a-x}

a-x=0.0169g

The amount left of carbon-14 = 0.0169 g

Now we have to calculate the percent of the carbon−14 left.

\text{Percent of carbon}-14\text{ left}=\frac{\text{Amount left of carbon}-14}{\text{Original amount of carbon}-14}\times 100

\text{Percent of carbon}-14\text{ left}=\frac{0.0169g}{7g}\times 100=0.242\%

Therefore, the percent of the carbon−14 left is, 0.242 %

8 0
3 years ago
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