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liq [111]
3 years ago
7

Match the wave with its definition. (Lesson 4.03-4.03)

Chemistry
1 answer:
Lady_Fox [76]3 years ago
6 0

The correct wave that matched its definition is:

  • Transverse Wave - A wave that has a disturbance that is perpendicular to the wave motion. The wave motion is moving side to side, the energy will be moving up and down.

  • Longitudinal Wave - The disturbance is parallel to the wave motion. In a longitudinal wave, the energy, and the motion

A wave is known to be a disturbance that travels through a medium and transfers energy from one point to another without causing any permanent displacement of the medium itself.

We have two forms of wave namely the transverse waves and the longitudinal waves.

When the vibration of a medium is perpendicular to the wave direction, the kind of wave formed is known as a transverse wave.

When the vibration of a medium is parallel to the wave direction, the kind of wave formed is known as a longitudinal wave.

Learn more here: brainly.com/question/15923236

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Design an invitation you could use to calculate the density of a penny
Nataliya [291]
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7 0
2 years ago
2Mg + O2 → 2MgO<br><br> If you are burning 5.8332 g of Mg, how many grams of MgO will this make?
LekaFEV [45]
<h3>Answer:</h3>

9.6724 g MgO

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Stoichiometry</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] 2Mg + O₂ → 2MgO

[Given] 5.8332 g Mg

<u>Step 2: Identify Conversions</u>

[RxN] 2 mol Mg = 2 mol MgO

Molar Mass of Mg - 24.31 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of MgO - 24.31 + 16.00 = 40.31 g/mol

<u>Step 3: Stoichiometry</u>

  1. Set up:                              \displaystyle 5.8332 \ g \ Mg(\frac{1 \ mol \ Mg}{24.31 \ g \ Mg})(\frac{2 \ mol \ MgO}{2 \ mol \ Mg})(\frac{40.31 \ g \ MgO}{1 \ mol \ MgO})
  2. Multiply/Divide:                                                                                               \displaystyle 9.67241 \ g \ MgO

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 5 sig figs.</em>

9.67241 g MgO ≈ 9.6724 g MgO

5 0
3 years ago
Read 2 more answers
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